AWS Lambda 上的卷曲答案

【问题标题】：Curl on AWS LambdaAWS Lambda 上的卷曲
【发布时间】：2022-08-13 05:21:57
【问题描述】：

我用 Java 编写了一个简单的 aws lambda 函数：

我的处理程序看起来像这样

public class HelloAWS implements RequestHandler<Map<String,String>, Object>{

@Override
public Object handleRequest(Map<String,String> i, Context cntxt) {
        String input = i.values().toString();
        return \"Hello World via Lambda and Java!\" + input;
}

AWS 仪表板测试的输出看起来像我期望的那样： \"Hello World 通过 Lambda 和 Java！[value1, value2, value3]\"

我正在尝试使用 Ubuntu curl 重现此测试结果：

curl \"https://myUrl.lambda-url.us-east-1.on.aws/\" -X POST -H \"Content-type: application/json\" -d \'{\"key1\": \"value1\"}\'

这会产生一个错误：

An error occurred during JSON parsing: java.lang.RuntimeException
java.lang.RuntimeException: An error occurred during JSON parsing
Caused by: java.io.UncheckedIOException: com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token
 at [Source: (ByteArrayInputStream); line: 1, column: 84] (through reference chain: java.util.LinkedHashMap[\"headers\"])
    at com.amazonaws.services.lambda.runtime.serialization.factories.JacksonFactory$InternalSerializer.fromJson(JacksonFactory.java:184)
Caused by: com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token
 at [Source: (ByteArrayInputStream); line: 1, column: 84] (through reference chain: java.util.LinkedHashMap[\"headers\"])
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException.from(MismatchedInputException.java:59)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.reportInputMismatch(DeserializationContext.java:1445)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1219)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1129)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:63)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:10)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer._readAndBindStringKeyMap(MapDeserializer.java:527)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:364)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:29)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1719)
    at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1228)
    at com.amazonaws.services.lambda.runtime.serialization.factories.JacksonFactory$InternalSerializer.fromJson(JacksonFactory.java:182)

An error occurred during JSON parsing: java.lang.RuntimeException java.lang.RuntimeException: An error occurred during JSON parsing Caused by: java.io.UncheckedIOException: com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token at [Source: (ByteArrayInputStream); line: 1, column: 84] (through reference chain: java.util.LinkedHashMap[\"headers\"]) at com.amazonaws.services.lambda.runtime.serialization.factories.JacksonFactory$InternalSerializer.fromJson(JacksonFactory.java:184) Caused by: com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token at [Source: (ByteArrayInputStream); line: 1, column: 84] (through reference chain: java.util.LinkedHashMap[\"headers\"]) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.exc.MismatchedInputException.from(MismatchedInputException.java:59) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.reportInputMismatch(DeserializationContext.java:1445) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1219) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.DeserializationContext.handleUnexpectedToken(DeserializationContext.java:1129) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:63) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:10) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer._readAndBindStringKeyMap(MapDeserializer.java:527) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:364) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.deser.std.MapDeserializer.deserialize(MapDeserializer.java:29) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1719) at com.amazonaws.lambda.thirdparty.com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1228) at com.amazonaws.services.lambda.runtime.serialization.factories.JacksonFactory$InternalSerializer.fromJson(JacksonFactory.java:182)

我发现多个来源表明我应该能够像这样卷曲我的服务：

https://aws.amazon.com/blogs/aws/announcing-aws-lambda-function-urls-built-in-https-endpoints-for-single-function-microservices/

https://docs.aws.amazon.com/lambda/latest/dg/urls-invocation.html

为什么 Java 对仪表板测试和 curl 请求的处理方式不同？

标签： java amazon-web-services aws-lambda

【解决方案1】：

您可以使用 API 网关来配置您的 Lambda 函数，以便您可以通过 CURL 调用它。配置 API Gateway 后，您可以调用使用 Java Lambda 运行时 API 构建的 Lambda 函数，命令如下：

curl -XGET "https://xxxxqjko1o3.execute-api.us-east-1.amazonaws.com/cronstage/employee"

下面是一个 Java 示例，可引导您完成此过程。此示例中创建的 Lambda 函数还调用 AWS 服务，例如 Amazon DynamoDB。

Using Amazon API Gateway to invoke Lambda functions

更新

我刚刚测试了它，它工作正常。我的 Lambda 函数是使用此 Curl 命令调用的。

关于在不使用 API Gateway 的情况下调用独立的 Lambda 函数，请参阅这篇可能在此处有所帮助的新文章：

Announcing AWS Lambda Function URLs: Built-in HTTPS Endpoints for Single-Function Microservices

已确认 - 我关注了那篇新文章，它为您提供了一个 URL，您可以使用它通过 CURL 调用而无需 API 网关......

部署 JAR（Lambda 函数）时 - 确保选择此选项：

【讨论】：

但是 OP 使用的是 Lambda 函数 URL，而不是 API 网关，docs 似乎表明完全支持这个用例。
我会调查这个。这些文档状态 API 网关也用于此目的 -- docs.aws.amazon.com/lambda/latest/dg/services-apigateway.html
是的，您可以在 Lambda 之前使用 API Gateway，但函数 URL 的全部意义在于您不需要 API Gateway。
它在 Java 中工作——刚刚确认
我相信您的示例使用不同的接口而不是 handleRequest(Map<String,String> i, Context cntxt) - 我的问题是为什么仪表板测试的处理方式与 curl 不同 - 它在使用 handleRequest(Object i, Context cntxt)

【解决方案2】：

public class HelloAWS implements RequestHandler<APIGatewayV2HTTPEvent, APIGatewayV2HTTPResponse> {

  @Override
  public APIGatewayV2HTTPResponse handleRequest(APIGatewayV2HTTPEvent request, Context context) {
    return null;
  }

【讨论】：