【发布时间】:2017-03-28 23:26:03
【问题描述】:
为什么在执行某些函数后使用nullable = true,即使DataFrame中没有NaN值。
val myDf = Seq((2,"A"),(2,"B"),(1,"C"))
.toDF("foo","bar")
.withColumn("foo", 'foo.cast("Int"))
myDf.withColumn("foo_2", when($"foo" === 2 , 1).otherwise(0)).select("foo", "foo_2").show
当现在调用df.printSchema 时,nullable 将是false 对于两列。
val foo: (Int => String) = (t: Int) => {
fooMap.get(t) match {
case Some(tt) => tt
case None => "notFound"
}
}
val fooMap = Map(
1 -> "small",
2 -> "big"
)
val fooUDF = udf(foo)
myDf
.withColumn("foo", fooUDF(col("foo")))
.withColumn("foo_2", when($"foo" === 2 , 1).otherwise(0)).select("foo", "foo_2")
.select("foo", "foo_2")
.printSchema
但是现在,nullable 至少有一列是 true,而之前是 false。这怎么解释?
【问题讨论】:
标签: apache-spark apache-spark-sql apache-spark-dataset