如何过滤一组对象并根据特定值仅返回一个对象

Question

我有一个包含两个计划对象的数组：

[ { "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }, 
 { "id": "price_46r34dgqn4d7w4fdw3476r323", 
   "name": "Yearly Plan", 
   "price": 29900, 
   "interval": "year", 
   "currency": "usd",
 } ]

我要做的是使用一个值 (customerPlanId) 通过将其与 plan.id 匹配来找到正确的计划，然后返回正确的计划，如下所示：

{ "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }

我知道我可以映射计划并筛选出正确的计划，但是我怎样才能自己返回正确的计划对象呢？

Answer 1

const plan =  [ { "id": "price_aehdw424i7rxyeqiquedwuy", 
    "name": "Monthly Plan", 
    "price": 2900, 
    "interval": "month", 
    "currency": "usd",
  }, 
 { "id": "price_46r34dgqn4d7w4fdw3476r323", 
   "name": "Yearly Plan", 
   "price": 29900, 
   "interval": "year", 
   "currency": "usd",
 } ]

const filtered  = plan.find((x)=>x.id === yourId)

Answer 2

解决方案

你可以使用“Array.filter”方法

示例

Stackblitz Snippet