根据连续日期对指定的预订进行分组答案

【问题标题】：Groups the specified bookings based on their consecutive dates根据连续日期对指定的预订进行分组
【发布时间】：2022-07-17 18:57:04
【问题描述】：

var listForTestGroup = new List<Booking>
            {
                new Booking{Project="HR", Date= DateTime.Parse("01/02/2020") , Allocation= 10},
                new Booking{Project="CRM", Date= DateTime.Parse("01/02/2020") , Allocation= 15},
                new Booking{Project="HR", Date= DateTime.Parse("02/02/2020") , Allocation= 10},
                new Booking{Project="CRM", Date= DateTime.Parse("02/02/2020") , Allocation= 15},

                new Booking{Project="HR", Date= DateTime.Parse("03/02/2020") , Allocation= 15},
                new Booking{Project="CRM", Date= DateTime.Parse("03/02/2020") , Allocation= 15},
                new Booking{Project="HR", Date= DateTime.Parse("04/02/2020") , Allocation= 15},
                new Booking{Project="CRM", Date= DateTime.Parse("04/02/2020") , Allocation= 15}
                ,

                new Booking{Project="HR", Date= DateTime.Parse("05/02/2020") , Allocation= 15},
                new Booking{Project="CRM", Date= DateTime.Parse("05/02/2020") , Allocation= 15},
                new Booking{Project="ECom", Date= DateTime.Parse("05/02/2020") , Allocation= 15},
                new Booking{Project="ECom", Date= DateTime.Parse("06/02/2020") , Allocation= 10}

                ,

                new Booking{Project="CRM", Date= DateTime.Parse("06/02/2020") , Allocation= 15},
                new Booking{Project="ECom", Date= DateTime.Parse("07/02/2020") , Allocation= 10},
                new Booking{Project="CRM", Date= DateTime.Parse("07/02/2020") , Allocation= 15}

            };

          [
            { From:01/02/2020 , To:02/02/2020 , [{ Project:CRM , Allocation:15 },{ Project:HR , Allocation:10 }]  },
            { From:03/02/2020 , To:04/02/2020 , [{ Project:CRM , Allocation:15 },{ Project:HR , Allocation:15 }]  },
            { From:05/02/2020 , To:05/02/2020 , [{ Project:CRM , Allocation:15 },{ Project:HR , Allocation:15 },{ Project:ECom , Allocation:15 }]  },
            { From:06/02/2020 , To:07/02/2020 , [{ Project:CRM , Allocation:15 },{ Project:ECom , Allocation:10 }]  }
          ]

【问题讨论】：

你的分组逻辑是什么？
为什么05/02/2020没过两天？

标签： c# linq

【解决方案1】：

您的分组逻辑不清楚。您是按 4 人一组分组，还是按月分组？

按月分组：

var groupings = bookings
    .OrderBy(x => x.Date)
    .GroupBy(x => x.Date.ToString("yyyy-MM"))
    .Select(g => new 
    {
        From = g.Min(x => x.Date), 
        To = g.Max(x => x.Date), 
        Bookings = g.Select(x => new {x.Project, x.Allocation})
    });

按 4 分组：

var groupings = bookings
    .OrderBy(x => x.Date)
    .Select((b, i) => new { Index = i, Booking = b })
    .GroupBy(g => g.Index / 4)
    .Select(g => new 
    {
        From = g.Min(x => x.Booking.Date), 
        To = g.Max(x => x.Booking.Date), 
        Bookings = g.Select(x => new {x.Booking.Project, x.Booking.Allocation})
    });

【讨论】：

【解决方案2】：

这是一个有点棘手的问题

这就是问题想要的

listForTestGroup.
            GroupBy(x => x.Project).
            Select((g, idx) => new { Group = g, ProjectID = idx + 1 }).
            SelectMany(x => x.Group.Select(r => new { r.Date, r.Project, r.Allocation, x.ProjectID })).
            GroupBy(r => r.Date).
            Select((g, idx) => new { Group = g, Rank = idx + 1, SumProjectID = g.Sum(r => r.ProjectID), SumAllocation = g.Sum(r => r.Allocation) }).
            SelectMany(x => x.Group.Select(r => new { r.Date, r.Project, r.Allocation, Diff = r.Date.AddDays(-x.Rank), x.SumProjectID, x.SumAllocation })).
            GroupBy(r => new { r.Diff, r.SumProjectID, r.SumAllocation }).
            Select(r => new { From = r.Min(d => d.Date), To = r.Max(d => d.Date), Items = r.Select(s => new { s.Project, s.Allocation }).Distinct().ToList() }).
            OrderBy(r => r.From).
            ToList();

【讨论】：

【解决方案3】：

请试试这个代码，它可以帮助你。

 var groupings = bookings
                        .OrderBy(x => x.Date)
                        .GroupBy(x => x.Date.ToString("yyyy-MM"))
                        .Select(g => new BookingGrouping
                        {
                            From = g.Min(x => x.Date),
                            To = g.Max(x => x.Date),
                            Items = g.Select(x => new BookingGroupingItem() {Project= x.Project,Allocation= x.Allocation }).ToList()
                        }).ToList();

【讨论】：