Rust Diesel 一对一关系答案

【问题标题】：Rust Diesel one to one relationshipRust Diesel 一对一关系
【发布时间】：2022-07-14 04:08:32
【问题描述】：

嘿，我正在创建一个 api 来返回用户及其个人资料

我有两个来自两个独立数据库、用户和个人资料的表

fn handle(
        &mut self,
        query_strings: SearchUsersQueryStrings,
        _: &mut SyncContext<Self>,
    ) -> Self::Result {
        let gateway_conn: &PgConnection = &self.1.get().unwrap();
        let own_conn: &PgConnection = &self.0.get().unwrap();

        let pattern = format!("%{}%", query_strings.username);

        let found_users = users
            .filter(username.like(pattern))
            .get_results::<User>(gateway_conn)?;

        let profile = Profile::belonging_to(&found_users)
            .load::<Profile>(own_conn)?
            .grouped_by(&found_users);
 

        let data = found_users.into_iter().zip(profile).collect();

        Ok(data)
    }

这里不好的是数据类型结果是，解析起来太难看了

[
    [
        {
            "id": 22,
            "username": "412212512",
            "email": "1231q1222122@gmail.com",
            "avatar": null,
            "created_at": "2022-02-21T09:31:29.855851"
        },
        [
            {
                "id": 3,
                "user_id": 22,
                "status": "qqq",
                "description": "xxx",
                "created_at": "2022-03-07T22:53:17.491532",
                "updated_at": null,
                "deleted_at": null
            }
        ]
    ],
    [
        {
            "id": 25,
            "username": "1412drew212512",
            "email": "1231q11srew222122@gmail.com",
            "avatar": null,
            "created_at": "2022-02-21T10:37:04.588795"
        },
        []
    ],
]

但我想要这样的东西：

[
            {
                "id": 22,
                "username": "1412212512",
                "email": "1231q1222122@gmail.com",
                "avatar": null,
                "created_at": "2022-02-21T09:31:29.855851",
                "profile": {
                    "id": 3,
                    "user_id": 22,
                    "status": "qqq",
                    "description": "xxx",
                    "created_at": "2022-03-07T22:53:17.491532",
                    "updated_at": null,
                    "deleted_at": null
                
                },
           ....
           
]

如果我在配置文件查询中使用load func，它将返回Vec<Profile>，但每个用户都有一条配置文件记录，如果我不使用load 而使用first，那么我就不能使用grouped_by在它上面

【问题讨论】：

标签： rust relationship actix-web rust-diesel

【解决方案1】：

像这样创建一个名为 UserAPI 的 struct：

pub struct UserAPI {
    #[serde(flatten)]
    pub user: User,

    pub profile: Profile,
}

然后在压缩数据后这样做：

fn handle(
        &mut self,
        query_strings: SearchUsersQueryStrings,
        _: &mut SyncContext<Self>,
    ) -> Self::Result {
        let gateway_conn: &PgConnection = &self.1.get().unwrap();
        let own_conn: &PgConnection = &self.0.get().unwrap();

        let pattern = format!("%{}%", query_strings.username);

        let found_users = users
            .filter(username.like(pattern))
            .get_results::<User>(gateway_conn)?;

        let profile = Profile::belonging_to(&found_users)
            .load::<Profile>(own_conn)?
            .grouped_by(&found_users);
 

        let data = found_users.into_iter().zip(profile).collect();

        let users_with_profile: Vec<UserAPI> = data
                .into_iter()
                .map(|(user, profile)| {
    
                    UserAPI {
                        user,
                        profile,
                    }
                })
                .collect();

        Ok(users_with_profile)
    }

【讨论】：