【发布时间】:2022-07-04 22:51:15
【问题描述】:
我有一个如下所示的数据框 df:
df<-structure(list(hex = c(7L, 7L, 5L, 7L, 5L, 5L, 5L, 3L, 5L, 7L
), material_diff = list(c(0, 0, -1, 0, 0, 0), c(0, 0, -1, 0,
0, 0), c(0, 0, -1, 0, 0, 0), c(0, 0, -1, 0, 0, 0), c(0, 0, -1,
0, 0, 0), c(0, 0, -1, 0, 0, 0), c(0, 0, -1, 0, 0, 0), c(0, 0,
0, 0, -0.166666666666667, 0), c(0, 0, -1, 0, 0, 0), c(0, 0, -1,
0, 0, 0))), class = "data.frame", row.names = c(NA, -10L))
hex material_diff
1 7 0, 0, -1, 0, 0, 0
2 7 0, 0, -1, 0, 0, 0
3 5 0, 0, -1, 0, 0, 0
4 7 0, 0, -1, 0, 0, 0
5 5 0, 0, -1, 0, 0, 0
6 5 0, 0, -1, 0, 0, 0
7 5 0, 0, -1, 0, 0, 0
8 3 0.0000000, 0.0000000, 0.0000000, 0.0000000, -0.1666667, 0.0000000
9 5 0, 0, -1, 0, 0, 0
10 7 0, 0, -1, 0, 0, 0
我想对 material_diff 中的向量求和并按十六进制分组以返回以下内容:
hex material_diff
1 3 0.0000000, 0.0000000, 0.0000000, 0.0000000, -0.1666667, 0.0000000
2 5 0, 0, -5, 0, 0, 0
3 7 0, 0, -4, 0, 0, 0
如何做到这一点?
【问题讨论】:
标签: r