【问题标题】:Disable Button When EditText Is Empty Android Studio?当EditText为空Android Studio时禁用按钮?
【发布时间】:2022-06-12 04:44:50
【问题描述】:

我是新手,没有经验。我看到了一些禁用登录按钮的代码。我试图将它添加到代码中。但我没有成功。当字段为空时,按下登录按钮时应用程序停止。

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        binding = ActivityLoginBinding.inflate(getLayoutInflater());
        setContentView(binding.getRoot());

        auth = FirebaseAuth.getInstance();

        dialog = new ProgressDialog(this);
        dialog.setMessage("Logging in...");

        if(auth.getCurrentUser() != null) {
            startActivity(new Intent(LoginActivity.this, MainActivity.class));
            finish();
        }

        binding.submitBtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String email, pass;

                email = binding.emailBox.getText().toString();
                pass = binding.passwordBox.getText().toString();

                dialog.show();

                auth.signInWithEmailAndPassword(email, pass).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {
                        dialog.dismiss();

                        if(task.isSuccessful()) {
                            startActivity(new Intent(LoginActivity.this, MainActivity.class));
                            finish();
                        } else {
                            Toast.makeText(LoginActivity.this, task.getException().getLocalizedMessage(), Toast.LENGTH_SHORT).show();
                        }
                    }
                });
            }
        });

        binding.createNewBtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                startActivity(new Intent(LoginActivity.this, SignupActivity.class));
            }
        });
    }
}

【问题讨论】:

    标签: java android android-studio


    【解决方案1】:

    您应该检查email 模式和password,而不仅仅是检查空字段,您应该检查长度是否> 6,否则Firebase Auth 将抛出异常。为您的submitBtn 侦听器使用以下代码:

            binding.submitBtn.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
    
                    String email = binding.emailBox.getText().toString();
                    String pass = binding.passwordBox.getText().toString();
    
                    if (email.isEmpty()) {
                        binding.emailBox.setError("Email is required");
                        binding.emailBox.requestFocus();
                        return;
                    }
    
                    if (!Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
                        binding.emailBox.setError("Email is not valid");
                        binding.emailBox.requestFocus();
                        return;
                    }
    
                    if (pass.isEmpty()) {
                        binding.passwordBox.setError("Password is required");
                        binding.passwordBox.requestFocus();
                        return;
                    }
    
                    if (pass.length() < 6) {
                        binding.passwordBox.setError("Password is weak");
                        binding.passwordBox.requestFocus();
                        return;
                    }
                    
                    dialog.show();
    
                    auth.signInWithEmailAndPassword(email, pass).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                        @Override
                        public void onComplete(@NonNull Task<AuthResult> task) {
                            dialog.dismiss();
    
                            if(task.isSuccessful()) {
                                startActivity(new Intent(LoginActivity.this, MainActivity.class));
                                finish();
                            } else {
                                Toast.makeText(LoginActivity.this, task.getException().getLocalizedMessage(), Toast.LENGTH_SHORT).show();
                            }
                        }
                    });
                }
            });
    

    【讨论】:

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