尝试使用复制（JSON.stringify（结果））

Question

我在浏览器中使用控制台来使用 JS 抓取和排序内容。 这是我的代码

这是我的结果数组

var arr = [
"George\nPresident & Founder",

"content",

 "Ronald\nCountry Director, America",

 "content",

 "Kriss, PhD\nVice President",

 "content",

 "Joseph, MS\nDirector",

 "content",

 "Elizabeth\nDevelopment Operations",

 "content",

 "Lisa, MFA, MBA\nU.S. Content",

 "content.",

 "Natalia\nCountry Director"
]

这是我尝试过的：

  for(var i=0; len = result.length, i < len; i++){
    result[i]['something'] = [];
    if(i === 0){
        result[i].split('\n');
    }
    else if (i % 2 === 0) {
        result[i].split('\n');
    }
    console.log(result[i]);
    result[i]['test'].push(result[i]);

  }

返回结果[i]['something'] = [];未定义 但是当我 console.log(result[i]) 我得到正确的结果。我试图复制(JSON.stringify(result[i])) 但我只取回一个对象。

for(var i=0; len = result.length, i < len; i++){
    var arr = [];
    if(i === 0){
        result[i].split('\n');
    }
    else if (i % 2 === 0) {
        result[i].split('\n')
    }
    arr.push(result[i])
    // console.log(result[i]);
    console.log(arr);
  }

这不会拆分它们，它只是将它们推入数组。

当我 console.log(result[i]) 我得到： （这是对的，但它不是字符串，也不是数组；我也不能复制这个）

George
President & Founder

 content 

  Ronald
  Country Director America 

  content 

  Kriss PhD
  Vice President 

  content 

  Joseph MS
  Director 

  content 

  Elizabeth
  Development Operations 

  content 

  Lisa MFA MBA
  U.S. Content 

  content

  Natalia
  Country Director 

我的最终目标应该是这样的：

var result = [
["George"],
["President & Founder"],

[ "content" ],

[ "Ronald"]
["Country Director, America" ],

[ "content" ],

[ "Kriss, PhD"],
["Vice President" ],

[ "content" ],

[ "Joseph, MS"],
["Director" ],

[ "content" ],

[ "Elizabeth"],
["Development Operations" ],

[ "content" ],

[ "Lisa, MFA, MBA"],
["U.S. Content" ],

[ "content." ],

[ "Natalia"],
["Country Director" ],
[ "content." ]
]

我该怎么做才能得到结果[i] 并使用 copy(JSON.stringify(result)) 将其复制到我的剪贴板上？

Answer 1

其他答案似乎很有趣。我会建议一个稍长的，有几个 for 循环。

这是我想出的：

更新：我已经更新了它，现在你也更新了你的帖子。

function changeArr(array) {
    // create a temporary array
    let tempArr = [];
    
    // loop through the array which was passed as an argument
    for (let i = 0; i < array.length; i++) {
        let splitArr = array[i].split("\n");

        // splitArr returns an array containing the 2 strings which have been split

        // using the spread operator from ES6 we can spread out the elements and push them into tempArr
        tempArr.push(...splitArr);
    }
    
    // tempArr should now contain your end result
    return tempArr;
}

使用方法：

changeArr(arr);

/*
this will return:

=> [
    "George",
    "President & Founder",

    "content",

    "Ronald",
    "Country Director, America",

    "content",

    "Kriss, PhD",
    "Vice President",

    "content",

    "Joseph, MS",
    "Director",

    "content",

    "Elizabeth",
    "Development Operations",

    "content",

    "Lisa, MFA, MBA",
    "U.S. Content",

    "content",

    "Natalia",
    "Country Director",

    "content"
]

有了这个，您可以创建另一个名为 let result 的变量并将函数返回的任何内容存储在其中。

let result = changeArr(arr);

或者您可以将函数返回的任何内容分配给arr 变量。

arr = changeArr(arr);

Answer 2

我会生成一个对象数组。由于每个人在数组中有两行（除了 Natalia，她没有内容吗？），您可以循环遍历数组，一次跳转两个，将每个人的信息收集到一个对象中。

var arr = [
"George\nPresident & Founder",

"content",

 "Ronald\nCountry Director, America",

 "content",

 "Kriss, PhD\nVice President",

 "content",

 "Joseph, MS\nDirector",

 "content",

 "Elizabeth\nDevelopment Operations",

 "content",

 "Lisa, MFA, MBA\nU.S. Content",

 "content.",

 "Natalia\nCountry Director"
];

const result = [];
for (let i=0; i < arr.length; i+=2) {
  const nameParts = arr[i].split("\n");
  result.push({
    name: nameParts[0],
    title: nameParts[1],
    content: arr[i + 1]
  });
}

console.log(result);

Answer 3

删除 arr.push(result[i]) 并试试这个

  if (i % 2 == 0) {
      arr.push( result[i].split('\n'));
    }
else
{
   arr.push(["content"]);
}

Answer 4

您可以通过使用reduce 方法更轻松地实现您的目标，如下所示：

let arr = [
  "George\nPresident & Founder",
  "content",
  "Ronald\nCountry Director, America",
  "content",
  "Kriss, PhD\nVice President",
  "content",
  "Joseph, MS\nDirector",
  "content",
  "Elizabeth\nDevelopment Operations",
  "content",
  "Lisa, MFA, MBA\nU.S. Content",
  "content.",
  "Natalia\nCountry Director"
]
let result = arr.reduce((acc, str) => {
  str.split('\n').forEach(str => acc.push([str]));
  return acc;
}, [])
console.log(result)