【发布时间】:2022-06-10 20:47:10
【问题描述】:
大家好,我是 php 中的 niubbie。我的选项卡有问题。我希望他们点击的标签显示不同的主题。所有这些都使用 php 并调用 db。
我的数据库:
| giorno | pranzo | cena |
|---|---|---|
| lunedi | 12:00 | 20:00 |
| martedi | 12:00 | 20:00 |
| mercoledi | 12:00 | 20:00 |
| giovedi | 12:00 | 20:00 |
| venerdi | 12:00 | 20:00 |
日期由选项卡表示,当我点击不同的日期时,我希望它显示该特定日期的午餐和晚餐。
我的代码:
<section class="big-section bg-light-gray border-top border-color-medium-gray wow animate__fadeIn">
<div class="container">
<div class="row justify-content-center">
<div class="col-md-12 text-center margin-six-bottom">
<h6 class="alt-font text-extra-dark-gray font-weight-500">Orari</h6>
</div>
</div>
<div class="row justify-content-center">
<div class="col-12 col-lg-10 tab-style-05">
<div class="tab-box">
<!-- start tab navigation -->
<ul class="nav nav-tabs margin-7-rem-bottom md-margin-5-rem-bottom xs-margin-15px-lr align-items-center justify-content-center font-weight-500 text-uppercase">
<?php
$sql = "SELECT * FROM orari_ristorante ";
$risultato = mysql_query($sql) or die(mysql_error()."<br>Impossibile eseguire l'interrogazione");
$i=0;
while ($riga = mysql_fetch_assoc($risultato)){
?>
<?php if($i == 0){?>
<li class="nav-item alt-font"><a class="nav-link active" href="#tab-nine1" data-toggle="tab"><?php echo $riga['giorno'];?></a></li>
<?php }else{?>
<li class="nav-item alt-font"><a class="nav-link" href="#tab-nine1" data-toggle="tab"><?php echo $riga['giorno'];?></a></li>
<?php }
$i++;
}?>
</ul>
<!-- end tab navigation -->
</div>
<div class="tab-content">
<!-- start tab content -->
<div class="tab-pane med-text fade in active show" id="tab-nine1">
<div class="panel-group accordion-event accordion-style-04" id="accordion1" data-active-icon="icon-feather-minus" data-inactive-icon="icon-feather-plus">
<!-- start accordion item -->
<div class="panel border-color-black-transparent">
<div class="panel-heading">
<?php
$sql = "SELECT pranzo,cena FROM orari_ristorante LIMIT 1";
$risultato = mysql_query($sql) or die(mysql_error()."<br>Impossibile eseguire l'interrogazione");
while ($riga = mysql_fetch_assoc($risultato)){
?>
<span class="panel-time">Pranzo</span>
<a class="accordion-toggle" data-toggle="collapse" data-parent="#accordion1">
<div class="panel-title">
<span class="text-extra-dark-gray d-inline-block font-weight-500"><?php echo $riga['pranzo'] ;?></span>
</div>
</a>
<a href="#" class="btn btn-very-small btn-golden btn-round-edge-small section-link"><span class='prenota'>PRENOTA</span></a>
<span class="panel-time">Cena</span>
<a class="accordion-toggle" data-toggle="collapse" data-parent="#accordion1">
<div class="panel-title">
<span class="text-extra-dark-gray d-inline-block font-weight-500"><?php echo $riga['cena'] ;?></span>
</div>
</a>
<a href="#" class="btn btn-very-small btn-golden btn-round-edge-small section-link"><span class='prenota'>PRENOTA</span></a>
<?php
}
?>
</div>
</div>
</div>
</div>
<!-- end tab content -->
</div>
</div>
</div>
</div>
</section>
我的问题是每个选项卡都显示所有行而不是当天的特定行
【问题讨论】:
-
您的问题是什么?什么不起作用?你有任何错误吗?
-
嗨,如果我不清楚,很抱歉我的英语不是很好。我希望我的标签像这样工作星期一午餐:12:00 晚餐:12:00 星期二另一行相反,目前显示数据库中所有日期的所有时间的日期,如我上面附上的图片所示。我希望我已经说清楚了。我为我的英语深表歉意