【发布时间】:2012-07-31 05:10:45
【问题描述】:
我正在做一个测试项目,比如一个使用 wi-fi 连接的基本聊天程序。 我正在创建套接字来连接两个不同的设备,但我的问题是当我发送第一条消息时,它显示在另一个设备中。但如果我再次尝试发送,我可以在第一个日志中看到消息已发送,但它从未出现在第二个设备中。
我尝试在另一个线程中实现读取接收到的数据..或在异步任务中,但问题仍然存在。以下是我的两种实现方式:
单线程:
public void listenForSocket(){
thread = new Thread(new Runnable() {
public void run() {
Log.e("READDATAFROMSOCKET","READDATAFROMSOCKET");
try {
// sets the service running state to true so we can get it's state from other classes and functions.
serverSocket = new ServerSocket(DNSUtils.port);
client = serverSocket.accept();
client.setKeepAlive(true);
InputStream is = client.getInputStream();
Log.d("","is Size : "+is.available());
BufferedReader in = new BufferedReader(new InputStreamReader(is));
int readed = in.read();
Log.d("","readed bytes : "+readed);
String line = "";
while ((line = in.readLine()) != null) {
Log.i("","line : "+line);
changeText(line);
}
//client.close();
//serverSocket.close();
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
});
thread.start();
}
这里是 AsyncTask :
class ServerTask extends AsyncTask<Void, Void, Void>{
private String line = "";
@Override
protected Void doInBackground(Void... params) {
try {
Log.e("ASYNCTASK","ASYNCTASK");
// sets the service running state to true so we can get it's state from other classes and functions.
serverSocket = new ServerSocket(DNSUtils.port);
client = serverSocket.accept();
client.setKeepAlive(true);
InputStream is = client.getInputStream();
Log.d("","is Size : "+is.available());
BufferedReader in = new BufferedReader(new InputStreamReader(is));
int readed = in.read();
Log.d("","readed bytes : "+readed);
while ((line = in.readLine()) != null) {
Log.i("","line : "+line);
}
//client.close();
//serverSocket.close();
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
changeText(line);
}
}
更改文本(字符串); -
private void changeText(final String line) {
runOnUiThread(new Runnable() {
@Override
public void run() {
LinearLayout.LayoutParams params = new LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
params.gravity = Gravity.RIGHT;
TextView sendMsg = new TextView(MainActivity.this);
sendMsg.setText(DNSUtils.clientName+" : "+line);
sendMsg.setTextColor(Color.DKGRAY);
sendMsg.setTextSize(18);
layout.addView(sendMsg, params);
}
});
}
有什么办法可以解决这个问题吗?
另一个问题是,当我读取接收到的数据时,发送的字符串的第一个字母从不显示。它总是从第二个字母开始。
提前致谢。
【问题讨论】:
-
我认为后台服务更符合您的需求。只要您的
Activity绑定到它,它就会一直存在。完成代码后它不会完成,例如您的Threads或AsyncTasks
标签: android sockets android-asynctask