长文本的拆分功能因 VALUE 失败！错误

Question

我正在使用我在 Stackoverflow 上看到的一个函数：

Function EXTRACTELEMENT(Txt, n, Separator) As String
 EXTRACTELEMENT = Split(Application.Trim(Txt), Separator)(n - 1)
End Function

它正在拆分一个数据数组，如下所示：

sRN LMDscandata sRA LMDscandata 1 1 F97BBF 0 0 6D2A 6D2D 71F5A0FA 71F5FD85 0 0 7 0 0 1388 168 0 1 DIST1 3F800000 00000000 D9490 1388 5 6E2 0 1 6DC 6E3 0 6ED 0>

但是当我试图增加数据量时：

SRN LMDscandata SRA LMDscandata 1 1 F97BBF 0 0 FCDF FCE2 9DC90606 9DC9637B 0 0 7 0 0 1388 168 0 1 DIST1 3F800000 00000000 C3500 1388 3D 525 50B 518 508 51D 50A 51A 502 514 50F 502 51C 50E 51C 50E 4FF 509 505 50B 4F9 505 51B 513 516 501 50F 509 4FE 505 508 50C 507 50C 50E 51A 511 514 528 511 519 524 52E 526 522 524 535 534 52E 527 52F 52E 53D 52F 550 535 547 548 559 551 557 558 0 0 0 0 0 0

发生错误，VBA 返回错误窗口并且没有数据被拆分。我该如何解决？

这是完整的代码，我正在对其进行编码以测试传感器输出，我在其中接收一些 hex 和 ascii 格式的重要数据，然后转换为 dec 并制作一些图表。这是转换值的函数。 如果有人也可以提供一些关于 Sub 的提示，我将不胜感激。

    Sub ler()

Dim ncell
Dim vArr, col
Dim counter, elem_end As Integer
Dim rng1, rng2 As String

 Set ascii = ThisWorkbook.Worksheets("ASCII")
Set medidas = ThisWorkbook.Worksheets("Medidas")
'Valor da última linha preenchida da coluna A'
    ncell = ascii.Range("A65536").End(xlUp).Row
    'Número de elementos'
    elem_end = ascii.Range("B" & ncell).Value

    For counter = 1 To elem_end

    counterplus = counter + 2
    vArr = Split(Cells(1, counterplus).Address(True, False), "$")
Col_Letter = vArr(0)
 col = Col_Letter
Let rng1 = col & ncell
Let rng2 = "A" & ncell
   ascii.Range(rng1).NumberFormat = "@"
    ele = EXTRACTELEMENT(ascii.Range(rng2), counter, " ")
    ascii.Range(rng1).FormulaR1C1 = ele


    Next


    With ascii.Range(Cells(ncell, 1), Cells(ncell, counterplus))
 Set dist = .Find("DIST1", LookIn:=xlValues)
    If Not dist Is Nothing Then
        firstAddress = dist.Address
        Do
            dist1 = firstAddress
            Set dist = .FindNext(dist)
        Loop While Not dist Is Nothing And dist.Address <> firstAddress
    End If
End With


   data_col = ascii.Range(dist1).Column + 5
  data_num = ascii.Cells(ncell, data_col).Value
  dec_num = CLng("&H" & data_num)
  medidas.Range("A" & ncell).Value = dec_num

  For counter2 = 1 To data_num
  asc_value = ascii.Cells(ncell, data_col + counter2).Value
  Dec = CLng("&H" & asc_value)
  medidas.Cells(ncell, counter2 + 1).Value = Dec

  Next


End Sub

在B列中，有一个函数可以计算A列中数据的元素个数

Answer 1

你需要声明变量，你得到一个类型不匹配，至少第一个需要声明。

Function EXTRACTELEMENT(Txt As String, n As Long, Separator As String) As String
 EXTRACTELEMENT = Split(Application.Trim(Txt), Separator)(n - 1)
 End Function