【发布时间】:2021-08-18 11:45:37
【问题描述】:
所以目前我正在 PyQt5 中创建数独。所以,到目前为止,我有 Board.py,它只是生成新的板。目前我正在研究 Play.py,它应该能够单击空白方块并能够通过按下键盘按钮(按键)来更改它。在 Play.py 中,我已经完成了所有操作 - 所有数字都放入了一块板上,我可以单击按钮并启动按键。但是,按照我的编码方式,所有按钮都存储在一个列表中(我这样做是因为我希望代码看起来干净)并且它只更新最后一个按钮。我希望它更新最近单击的按钮,而不是更新最后一个按钮。
我已经尝试了很多事情,但我目前将其缩小到的是在所有按钮(all_buttons)列表中找到按钮的位置并从那里做一些事情,但我不确定。那么,我如何才能将按键按下并将其放入最近按下的按钮中?
这里是 Board.py。它只是生成了不需要查看的新板。
import random
import numpy as np
# populates a row in random spaces
def populate():
row = [0] * 9
num_in_box = random.randint(3, 6)
while True:
spot = random.randint(0, 8)
r = random.randint(1, 9)
if r not in row:
row[spot] = r
if row.count(0) == (9 - num_in_box):
break
return row
# populates a grid in random spaces - has duplicates in column, row and box
mapped = list()
for x in range(9): mapped.append(populate())
# checks every number in column and row and returns numbers in list
def col_row_nums(array, row, col):
check_col = [j for j in array[:, col] if j != 0]
check_row = [i for i in array[row] if i != 0]
if array[row][col] in check_col:
check_col.remove(array[row][col])
return check_col + check_row
# checks every number box and returns numbers in list
def box_nums(array, box_row):
reshaped_box = np.reshape(array, (27, 3))
list_boxes_in_rows = list()
for a in range(3):
for b in range(3):
for c in range(3):
p2 = list(np.reshape((reshaped_box[c::3]), (3, 9)))
for d in range(3): list_boxes_in_rows.append(p2[a])
array_boxes_in_rows = np.array(list_boxes_in_rows)
return [k for k in array_boxes_in_rows[box_row] if k != 0]
# removes any duplicates so each column, row and box all have only one set of numbers 1 - 9
def finalize_board():
box_rows_num = -1
for x in range(9):
for y in range(9):
box_rows_num += 1
arr = np.array(mapped)
possible_nums = [1, 2, 3, 4, 5, 6, 7, 8, 9]
col_row_duplicates = list()
box_duplicates = list()
used_nums = set(col_row_nums(arr, x, y)) | set(box_nums(arr, box_rows_num))
for w in used_nums:
col_row_count = col_row_nums(arr, x, y).count(w)
box_count = box_nums(arr, box_rows_num).count(w)
if col_row_count > 1: col_row_duplicates.append(w)
if box_count > 1: box_duplicates.append(w)
if mapped[x][y] in col_row_duplicates or mapped[x][y] in box_duplicates:
remaining_nums = list(set(possible_nums) - set(used_nums))
if len(remaining_nums) > 0: mapped[x][y] = random.choice(remaining_nums)
return mapped
接下来是 Play.Py。
import sys
from pynput import keyboard
from PyQt5 import QtWidgets as qtw
from PyQt5 import QtCore as qtc
from PyQt5 import QtGui as qtg
import Board
class MainWindow(qtw.QWidget):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
# -------------------------------------------------------------------------------------------
all_buttons = list()
layout = qtw.QGridLayout()
layout.setSpacing(0)
board = Board.finalize_board()
y_num = -1
for x, rows in enumerate(board):
for y, cell in enumerate(rows):
y += 1
if cell == 0: cell = ' '
button = qtw.QPushButton(str(cell), self)
button.setFixedHeight(100)
button.setFixedWidth(100)
layout.addWidget(button, x, y)
if cell == ' ':
button.clicked.connect(lambda: pressed())
button.setStyleSheet('QPushButton {background-color: #e3efff; color: black;}')
else:
button.setEnabled(False)
button.setStyleSheet('QPushButton {background-color: #ebebeb; color: black;}')
all_buttons.append(button)
def pressed():
with keyboard.Events() as events:
# maybe - ?? HOW TO RETURN POSITION OF BUTTON IN ALL_BUTTONS
event = events.get(1e6)
x = event.key
print(str(x))
button.setText(str(x))
self.setLayout(layout)
# -------------------------------------------------------------------------------------------
self.show()
if __name__ == '__main__':
app = qtw.QApplication(sys.argv)
w = MainWindow()
sys.exit(app.exec_())
【问题讨论】: