如何在 LinearLayout 中获取 ImageView 的坐标和大小

Question

当我点击按钮时，调用drawDigit()，puzzleview只是Activity中的一个LinearLayout

protected void drawDigit(Canvas canvas, int digit) {
        // TODO Auto-generated method stub
        if(num < diff){
            int x = tiles.get(num).getScrollX();  // get the X coordinate of ImageView，it's 0
            int y = tiles.get(num).getScrollY();  // get the Y coordinate of ImageView，it's 0
            float height = tiles.get(num).getHeight(); // height is 0
            float width = tiles.get(num).getWidth();   // width is 0
            background.setTextSize(height * 0.75f);
            background.setStyle(Style.FILL);
            background.setTextScaleX(width/height);
            background.setTextAlign(Paint.Align.CENTER);
            canvas.drawText(digit + "", x, y, background);
            //num++;
        }
    }

如何将布局中的ImageView 分配给图块，然后获取坐标和大小？

Answer 1

你可以试试这个：

//这是为了获取布局中固定的ImageView大小

int imageHeight;
int imageWidth;

ImageView imageViewObj = (ImageView)findViewById(R.id.image_view_id);
ViewTreeObserver treeObsObj = imageViewObj.getViewTreeObserver();
treeObsObj.addOnPreDrawListener(new ViewTreeObserver.OnPreDrawListener() {

    public boolean onPreDraw() {
    imageWidth= imageViewObj.getMeasuredWidth();
    imageHeight = imageViewObj.getMeasuredHeight();
    return true;
}
});

// 获取 ImageView 中图像的大小，并且大小会有所不同
**// 在您放置在 ImageView 中的图像上

ImageView imageObj = (ImageView)findViewById(R.id.image_view_id);
int imageWidth = imageObj.getWidth();
int imageHeight = imageObj.getHeight();