如何通过条件标记 id？答案

【问题标题】：How to flag id's by a condition?如何通过条件标记 id？
【发布时间】：2022-01-06 13:33:27
【问题描述】：

我想创建一个标记 id 的列，它有一个直接的订单流程。即没有 order_status pending 或 info_required 的 id。

例如id a 有待处理，所以is_straight 将是假的。 b 没有pending 或info_required，所以它应该是真的。

这是示例数据：

    WITH t1 AS (
SELECT 'a' AS id, 'created' AS status, '2021-11-02 15:04:07'::timestamp AS created_at UNION ALL
SELECT 'a' AS id, 'created' AS status, '2021-11-03 13:23:34'::timestamp AS created_at UNION ALL
SELECT 'a' AS id, 'pending' AS status, '2021-11-07 04:04:46'::timestamp AS created_at UNION ALL
SELECT 'a' AS id, 'successful' AS status, '2021-11-07 13:25:05'::timestamp AS created_at UNION ALL
SELECT 'b' AS id, 'created' AS status, '2021-11-11 16:19:07'::timestamp AS created_at UNION ALL
SELECT 'b' AS id, 'successful' AS status, '2021-11-13 17:57:55'::timestamp AS created_at UNION ALL
SELECT 'c' AS id, 'created' AS status, '2021-11-15 01:09:23'::timestamp AS created_at UNION ALL
SELECT 'c' AS id, 'info_required' AS status, '2021-11-17 11:06:00'::timestamp AS created_at UNION ALL
SELECT 'c' AS id, 'successful' AS status, '2021-11-21 23:35:46'::timestamp AS created_at
    )

【问题讨论】：

标签： sql snowflake-cloud-data-platform window-functions

【解决方案1】：

使用窗口化COUNT_IF:

SELECT *,
   COUNT_IF(order_status IN ('pending', 'info_required')) OVER(PARTITION BY id) = 0 
            AS is_straight
FROM t1;

输出：

【讨论】：