回收站查看 |最快的 smoothScrollToPosition 动画

Question

问题基于真实场景，我简化了用例：

假设我们有一个值从 0 到 999 的微调器和回收视图。 此外，除了常规的回收器滑动选项，用户还可以从微调器中选择一个数字，回收器将滚动到索引。

问题：当当前页面和新的微调器值之间的差异很大时（例如，我们在位置 0，现在用户选择来自微调器 400）。

下面是代码（item layout 只包含 textview）：

public class MainActivity extends AppCompatActivity {
    RecyclerView recyclerView;
    Spinner spinner;
    List<Integer> items = new ArrayList<>();
    ItemAdapter adapter;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        // init "database"
        for (int i = 0; i < 1000; i++)
            items.add(i);

        // Spinner
        spinner = (Spinner) findViewById(R.id.spinner);
        final ArrayAdapter<Integer> spinnerAdapter = new ArrayAdapter<Integer>(this, R.layout.support_simple_spinner_dropdown_item, items);
        spinner.setAdapter(spinnerAdapter);
        spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
            @Override
            public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
                recyclerView.smoothScrollToPosition(i);
            }

            @Override
            public void onNothingSelected(AdapterView<?> adapterView) {

            }
        });

        // Recycle View
        recyclerView = (RecyclerView) findViewById(R.id.recycler_view);
        LinearLayoutManager linearLayoutManager = new LinearLayoutManager(this, LinearLayoutManager.HORIZONTAL, false);
        adapter = new ItemAdapter();
        recyclerView.setLayoutManager(linearLayoutManager);
        recyclerView.setAdapter(adapter);
    }

    public class ItemAdapter extends RecyclerView.Adapter<ViewHolder>
    {

        @Override
        public ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
            View v = LayoutInflater.from(parent.getContext())
                    .inflate(R.layout.item, parent, false);
            ViewHolder vh = new ViewHolder(v);
            return vh;
        }

        @Override
        public void onBindViewHolder(ViewHolder holder, int position) {
            holder.tvIndex.setText(String.valueOf(position));
        }

        @Override
        public int getItemCount() {
            return items.size();
        }
    }

    private class ViewHolder extends RecyclerView.ViewHolder {
        TextView tvIndex;

        public ViewHolder(View itemView) {
            super(itemView);
            tvIndex = (TextView) itemView.findViewById(R.id.tv_index);
        }
    }
}

问题：当需要滑动很多页面时，如何执行“快速滚动”？

编辑：我想要动画，但要短。

Answer 1

recyclerView.scrollToPosition(i-5);然后 recyclerView.smoothScrollToPosition(i);但请记住根据您的用途验证此 "i"。