【发布时间】：2018-05-22 16:45:05
【问题描述】：
我在 Web 应用程序中配置 spring-data-ldap 时遇到问题。 我总结了我所做的： 我创建了一个maven（称为ldap-model）项目，带有spring-data-ldap依赖，我创建了User.java（Entry）类和对应的Repository：UserRepository。 然后我创建了一个新的spring mvc web项目，使用之前创建的解放依赖（ldap-model）。 我想使用xml配置，所以：
根上下文.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:ldap="http://www.springframework.org/schema/ldap"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/ldap http://www.springframework.org/schema/ldap/spring-ldap.xsd">
<!-- Root Context: defines shared resources visible to all other web components -->
<context:property-placeholder location="classpath:ldap.properties" />
<context:annotation-config />
<ldap:context-source id="contextSource"
password="${ldap.contextSource.password}" url="${ldap.contextSource.url}"
username="${ldap.contextSource.userDn}" base="${ldap.contextSource.base}"></ldap:context-source>
<ldap:repositories base-package="eu.test.ldap.repository">
</ldap:repositories>
<ldap:ldap-template id="ldapTemplate"
context-source-ref="contextSource"></ldap:ldap-template>
<bean class="eu.test.webapp.UserService">
</bean>
这里我有标签 ldap:repositories 的第一个问题，向我建议使用 Ctrl + Space，但它不会编译给出此错误：
Multiple annotations found at this line:
- Configuration problem: Cannot locate BeanDefinitionParser for element [repositories] Offending resource: file [C:/Progetti/
Workspace di test/ldap-webapp/src/main/webapp/WEB-INF/spring/root-context.xml]
- Cannot locate BeanDefinitionParser for element [repositories]
接下来的代码：
用户服务.java
public class UserService implements BaseLdapNameAware {
private final UserRepository userRepo;
private LdapName baseLdapPath;
@Autowired
public UserService(UserRepository userRepo) {
this.userRepo = userRepo;
}
public void find()
{
User u = userRepo.findByUid("test.test");
System.out.println(u.getUid());
}
@Override
public void setBaseLdapPath(LdapName baseLdapPath) {
this.baseLdapPath = baseLdapPath;
}}
ldap.properties
ldap.contextSource.url=*********
ldap.contextSource.userDn=cn=*********
ldap.contextSource.password=*********
ldap.contextSource.base=*********
servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="eu.test.webapp" />
HomeController.java
@Controller
public class HomeController {
private static final Logger logger = LoggerFactory.getLogger(HomeController.class);
@Autowired
private UserService userService;
@RequestMapping(value = "/", method = RequestMethod.GET)
public String home(Locale locale, Model model) {
logger.info("Welcome home! The client locale is {}.", locale);
userService.find();
return "home";
}
}
除了给出的错误之外还有什么问题吗？
我也尝试创建一个 java 配置，而不是 xml 我新建了一个spring mvc web项目，之前创建了解放依赖（ldap-model）。
@Configuration
@PropertySource("classpath:ldap.properties")
@ComponentScan(basePackages = {"eu.test.*"})
@Profile("default")
@EnableLdapRepositories(basePackages = "eu.test.ldap.repository.**")
public class AppConfig {
@Autowired
private Environment env;
@Bean
public LdapContextSource contextSource() {
LdapContextSource contextSource = new LdapContextSource();
contextSource.setUrl(env.getRequiredProperty("ldap.contextSource.url"));
contextSource.setBase(env.getRequiredProperty("ldap.contextSource.base"));
contextSource.setUserDn(env.getRequiredProperty("ldap.contextSource.userDn"));
contextSource.setPassword(env.getRequiredProperty("ldap.contextSource.password"));
return contextSource;
}
@Bean
public LdapTemplate ldapTemplate() {
return new LdapTemplate(contextSource());
}
}
类似上面的ldap.properties
用户服务.java
@Service
公共类用户服务{
@Autowired
private UserRepository userRepository;
public String getUsernameByUid(String uid)
{
return userRepository.findByUid(uid).getUsername();
}
}
HomeController.java
@Controller
public class HomeController {
private static final Logger logger = LoggerFactory.getLogger(HomeController.class);
@Autowired
private UserService userService;
@RequestMapping(value = "/", method = RequestMethod.GET)
public String home(Locale locale, Model model) {
String username = userService.getUsernameByUid("nome.cognome");
return "home";
}
}
我确定缺少某些东西，userService 为空
有人有具有这些功能的示例网络项目吗？
对不起，英语不好，谢谢。
【问题讨论】：
标签： java spring spring-mvc ldap