在雪花中查询列表答案

【问题标题】：Querying List in Snowflake在雪花中查询列表
【发布时间】：2021-10-02 21:00:53
【问题描述】：

我在 Snowflake 中有一张如下表

+---------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|attrs          |options                                                                                                                                                                                                                                                                                            |
+---------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|acct           |[{"key":"spencer","val":"spencer"},{"key":"mart","val":"mart"},{"key":"red-fin","val":"-"}]                                                                                                                                                                                                        |
|fav_activity   |[{"key":"movie","val":"movie"},{"key":"books","val":"books"},{"key":"music","val":"music"},{"key":"swimming","val":"swimming"},{"key":"games","val":"games"},{"key":"team","val":"team"},{"key":"food","val":"food"},{"key":"steam-room","val":"\"steam room\""},{"key":"hiking","val":"hiking"}]  |
+---------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

现在我需要比较字典列表的每个键和值，并只返回键/值不同的字典的键。

例如，查看 attrs acct - 列表中有 3 个字典。前两个字典的键和值是相同的，但第三个具有不同的键/值。所以我需要返回第三个字典的键red-fin

预期输出：

+---------------+------------+
|attrs          |result      |
+---------------+------------+   
|acct           |red-fin     |
|fav_activity   |steam-room  |
+---------------+------------+

谁能帮我在雪花中做这个。

提前致谢。

【问题讨论】：

标签： snowflake-cloud-data-platform snowflake-schema snowflake-sql

【解决方案1】：

你只需要展平和比较。

这解决了示例测试用例：

with data as (
select $1 attrs, parse_json($2) options   
from values ('acct', '[{"key":"spencer","val":"spencer"},{"key":"mart","val":"mart"},{"key":"red-fin","val":"-"}]')
, ('fav_activity', '[{"key":"movie","val":"movie"},{"key":"books","val":"books"},{"key":"music","val":"music"},{"key":"swimming","val":"swimming"},{"key":"games","val":"games"},{"key":"team","val":"team"},{"key":"food","val":"food"},{"key":"steam-room","val":"\\"steam room\\""},{"key":"hiking","val":"hiking"}]')
)

select attrs, k.value:key
from data, table(flatten(options)) k
where k.value:key!=k.value:val
;

【讨论】：