如何获取 XDocument 子节点

Question

<Users>
  <Account>
    <User>
      <Username>AdminUser</Username>
      <Password>pass123</Password>
      <Active>true</Active>
      <Account>Admin</Account>
      <Details>
  	<Account>xyz</Account>
      </Details>
    </User>   
  </Account>
 <Account>
    <User>
      <Username>AdminUser</Username>
      <Password>pass123</Password>
      <Active>true</Active>
      <Account>Admin</Account>
      <Details>
  	<Account>xyz</Account>
      </Details>
    </User>   
  </Account>
 <Account>
    <User>
      <Username>AdminUser</Username>
      <Password>pass123</Password>
      <Active>true</Active>
      <Account>Admin</Account>
      <Details>
  	<Account>xyz</Account>
      </Details>
    </User>   
  </Account>
</Users>

反序列化后，我得到了如上所示的 XDocument。 “Account”节点有同名的子节点，即Account。如何获取“Users”节点的所有子节点意味着我想在“Users”节点下获得三个“Account”节点。

Answer 1

IEnumerable<XElement> accounts = doc.Root.Elements("Account");

在此示例中，Accounts 是唯一的直接子级，您可以使用 this overload：

IEnumerable<XElement> accounts = doc.Root.Elements();

你应该使用XContainer.Elements("name") 来获取直接子元素，或者XContainer.Descendants("name") 如果你想获取所有同名的嵌套元素。

Answer 2

 XDocument doc = XDocument.Load(path);
        foreach (XElement element in doc.Root
                              .Element("Account")
                              .Elements("User"))
        {
            Console.WriteLine("Username: {0}; Password: {1}; Active:{2}; Account: {3}; Details Account: {4}",
                              (string)element.Element("Username"),
                              (string)element.Element("Password"),
                              (string)element.Element("Active"),
                              (string)element.Element("Account"),
                              (string)element.Element("Details").Element("Account"));
        }

Answer 3

如果我理解正确，请尝试使用Xpath Query（已测试并通过）

    var xml_string = "<Users>  <Account>    <User>      <Username>AdminUser</Username>      <Password>pass123</Password>      <Active>true</Active>      <Account>Admin</Account>      <Details>    <Account>xyz</Account>      </Details>    </User>     </Account> <Account>    <User>      <Username>AdminUser</Username>      <Password>pass123</Password>      <Active>true</Active>      <Account>Admin</Account>      <Details>      <Account>xyz</Account>      </Details>    </User>     </Account> <Account>    <User>      <Username>AdminUser</Username>      <Password>pass123</Password>      <Active>true</Active>      <Account>Admin</Account>      <Details>      <Account>xyz</Account>      </Details>    </User>     </Account></Users>";

    var xmlNodes = xml.SelectNodes("Users/Account/User");

    foreach (XmlNode node in xmlNodes)
    {
      Console.WriteLine("Username: {0}; Password: {1}; Active:{2}; Account: {3}; Details Account: {4}",
                                node["Username"].InnerText,
                                node["Password"].InnerText,
                                node["Active"].InnerText,
                                node["Account"].InnerText,
                                node["Details"].InnerText);
    }

  //result is

   // Username: AdminUser; Password: pass123; Active:true; Account: Admin; Details Account: xyz
   // Username: AdminUser; Password: pass123; Active:true; Account: Admin; Details Account: xyz
  // Username: AdminUser; Password: pass123; Active:true; Account: Admin; Details Account: xyz"

在Account节点下获取3个User节点

或者这个：获取Users/Account下的3个Account节点

            var xml = new XmlDocument();

            xml.LoadXml(xml_string);

            var xmlNodes = xml.SelectNodes("Users/Account/User/Account");

            foreach (XmlNode node in xmlNodes)
            {
               Console.WriteLine(node.InnerText);
            }

           //result is 

            //Admin
            //Admin
            //Admin