【发布时间】:2017-01-07 13:08:02
【问题描述】:
这是我第一次在这个论坛上提问,所以就这样吧。我正在创建一个用于练习的井字游戏,并且正在使用枚举器和递归,因为我从未真正做过枚举,并且总是可以进行一些递归练习。无论如何,我刚刚完成了 player2 的编码以进行随机移动,然后大约 3 圈它给出了一个分段错误,我不知道为什么......我希望你们能弄清楚,谢谢!
#include <iostream>
#include <string>
#include <cstdlib>
const int size = 3;
enum play {none,X,O};
void NPC(play (&board)[size][size],play player2) {
srand(time(NULL));
int tempx = rand() % 3;
int tempy = rand() % 3;
if(board[tempx][tempy] == none)
board[tempx][tempy] = player2;
else
NPC(board,player2);
}
void getBoardState(play (&board)[size][size],int y,int x) {
if(board[x][y] == none) std::cout << " ";
else if(board[x][y] == X) std::cout << "X";
else std::cout << "O";
}
void printboard(play (&board)[size][size]){
int length = 4 * size - 1;
for(int i = 1; i <= length; i++) {
for(int j = 1; j <= length; j++) {
if(i % 4 == 0 && j % 4 == 0) std::cout << "+";
else if(i % 4 == 0) std::cout << "-";
else if(j % 4 == 0) std::cout << "|";
else if(i % 2 == 0 && j % 2 == 0) getBoardState(board,(i - 2)/4,(j - 2)/4);
else std::cout << " ";
}
std::cout << std::endl;
}
}
int main() {
play player = O, player2 = X;
bool over = false;
play board[size][size];
for(int i = 0; i < size; i++) {
for(int j = 0; j < size; j++) {
board[i][j] = none;
}
}
std::string player1 = "";
std::cout << "What would You like to be? An X or an O?" << std::endl;
while(((player1 != "X") + (player1 != "O")) == 2) {
std::cin >> player1;
if(((player1 != "X") + (player1 != "O")) == 2)
std::cout << "Invalid entry! Please enter X or an 0!" << std::endl;
}
if(player1 == "X") {
player2 = O;
player = X;}
int tempx,tempy;
while(!over) {
std::cout << "Please enter an x and then a y (1 to " << size << ")" << std::endl;
std::cin >> tempx;
std::cin >> tempy;
while(tempx > size || tempy > size || board[tempx-1][tempy-1] != none) {
std::cout << "Invalid entry! Try again!" << std::endl;
std::cin >> tempx;
std::cin >> tempy;
}
board[tempx-1][tempy-1] = player;
NPC(board,player2);
printboard(board);
}
return 0;
}
【问题讨论】:
-
板子满了需要退出,否则NPC函数会永远递归。