【发布时间】:2020-05-05 15:23:28
【问题描述】:
游戏不会重置上次游戏的输入。它具有第一个游戏的输入,并且不会在询问用户是否想再次玩的循环中重置。我尝试制作一个 void 函数,通过拥有两个相同的数组来重置代码的值,但它仍然不起作用。请帮忙,因为我对 c++ 还很陌生。
#include <iostream>
using namespace std;
char matrix[3][3] = { '1', '2', '3', '4', '5', '6', '7', '8', '9' };
const char matrix2[3][3] = { '1', '2', '3', '4', '5', '6', '7', '8', '9' };
char player = 'X';
int n;
int xscore = 0, oscore = 0, gamenum = 1;
void Draw()
{
system("cls");
cout << "T i c T a c T o e" << endl;
cout << "Game #" << gamenum << " Score: X - [" << xscore << "] O - [" << oscore << "]" << endl;
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
cout << matrix[i][j] << " ";
}
cout << endl;
}
}
void Input()
{
int a;
cout << "It's " << player << " turn. " <<"Press the number of the field: ";
cin >> a;
if (a == 1)
{
if (matrix[0][0] == '1')
matrix[0][0] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 2)
{
if (matrix[0][1] == '2')
matrix[0][1] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 3)
{
if (matrix[0][2] == '3')
matrix[0][2] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 4)
{
if (matrix[1][0] == '4')
matrix[1][0] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 5)
{
if (matrix[1][1] == '5')
matrix[1][1] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 6)
{
if (matrix[1][2] == '6')
matrix[1][2] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 7)
{
if (matrix[2][0] == '7')
matrix[2][0] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 8)
{
if (matrix[2][1] == '8')
matrix[2][1] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
else if (a == 9)
{
if (matrix[2][2] == '9')
matrix[2][2] = player;
else
{
cout << "Number is already filled try again." << endl;
Input();
}
}
}
void TogglePlayer()
{
if (player == 'X')
player = 'O';
else
player = 'X';
}
char Win()
{
//first player
if (matrix[0][0] == 'X' && matrix[0][1] == 'X' && matrix[0][2] == 'X')
return 'X';
if (matrix[1][0] == 'X' && matrix[1][1] == 'X' && matrix[1][2] == 'X')
return 'X';
if (matrix[2][0] == 'X' && matrix[2][1] == 'X' && matrix[2][2] == 'X')
return 'X';
if (matrix[0][0] == 'X' && matrix[1][0] == 'X' && matrix[2][0] == 'X')
return 'X';
if (matrix[0][1] == 'X' && matrix[1][1] == 'X' && matrix[2][1] == 'X')
return 'X';
if (matrix[0][2] == 'X' && matrix[1][2] == 'X' && matrix[2][2] == 'X')
return 'X';
if (matrix[0][0] == 'X' && matrix[1][1] == 'X' && matrix[2][2] == 'X')
return 'X';
if (matrix[2][0] == 'X' && matrix[1][1] == 'X' && matrix[0][2] == 'X')
return 'X';
//second player
if (matrix[0][0] == 'O' && matrix[0][1] == 'O' && matrix[0][2] == 'O')
return 'O';
if (matrix[1][0] == 'O' && matrix[1][1] == 'O' && matrix[1][2] == 'O')
return 'O';
if (matrix[2][0] == 'O' && matrix[2][1] == 'O' && matrix[2][2] == 'O')
return 'O';
if (matrix[0][0] == 'O' && matrix[1][0] == 'O' && matrix[2][0] == 'O')
return 'O';
if (matrix[0][1] == 'O' && matrix[1][1] == 'O' && matrix[2][1] == 'O')
return 'O';
if (matrix[0][2] == 'O' && matrix[1][2] == 'O' && matrix[2][2] == 'O')
return 'O';
if (matrix[0][0] == 'O' && matrix[1][1] == 'O' && matrix[2][2] == 'O')
return 'O';
if (matrix[2][0] == 'O' && matrix[1][1] == 'O' && matrix[0][2] == 'O')
return 'O';
return '/';
}
void gamereset()
{
for (int g = 0; g < 3; g++)
{
for (int h = 0; h < 3; h++)
{
matrix2[g][h] == matrix[g][h];
}
}
}
int main()
{
char user;
do{
n = 0;
Draw();
while (1)
{
n++;
Input();
Draw();
if (Win() == 'X')
{
cout << "X wins!" << endl;
xscore++;
break;
}
else if (Win() == 'O')
{
cout << "O wins!" << endl;
oscore++;
break;
}
else if (Win() == '/' && n == 9)
{
cout << "It's a draw!" << endl;
break;
}
TogglePlayer();
}
cout << "Do you want to play again[Y/N]:";
cin >> user;
gamenum++;
gamereset();
}
while(user == 'Y' or user == 'y');
}
如您所见,gamreset() 函数不起作用。我尝试了很多方法来弄清楚如何重置它,但它仍然不起作用。
【问题讨论】:
-
如果你在编译代码时启用了警告,你的编译器应该会告诉你
matrix2[g][h] == matrix[g][h]什么都不做。改为matrix[g][h] = matrix2[g][h]。 -
你知道
'1' == '0' + a和matrix[0][0] == matrix[(a-1) / 3][(a-1) % 3]对应a = 1吗?这适用于矩阵的所有字段。您可以使用它来删除 if-else 级联。这是一个例子:wandbox.org/permlink/Hu7lkbsDXOPeDIZM