【发布时间】:2017-01-12 02:53:30
【问题描述】:
我已按照this posting 的说明从现有 Postgres 数据库中读取数据,该数据库中的表名为“objects”,该表由 SQLalchemy 中的Objects 类定义和创建。在我的 Jupyter 笔记本中,我的代码是
from pyspark import SparkContext
from pyspark import SparkConf
from random import random
#spark conf
conf = SparkConf()
conf.setMaster("local[*]")
conf.setAppName('pyspark')
sc = SparkContext(conf=conf)
from pyspark.sql import SQLContext
sqlContext = SQLContext(sc)
properties = {
"driver": "org.postgresql.Driver"
}
url = 'jdbc:postgresql://PG_USER:PASSWORD@PG_SERVER_IP/db_name'
df = sqlContext.read.jdbc(url=url, table='objects', properties=properties)
最后一行结果如下:
Py4JJavaError: An error occurred while calling o25.jdbc.
: java.lang.NullPointerException
at org.apache.spark.sql.execution.datasources.jdbc.JDBCRDD$.resolveTable(JDBCRDD.scala:158)
at org.apache.spark.sql.execution.datasources.jdbc.JDBCRelation.<init>(JDBCRelation.scala:117)
at org.apache.spark.sql.DataFrameReader.jdbc(DataFrameReader.scala:237)
at org.apache.spark.sql.DataFrameReader.jdbc(DataFrameReader.scala:159)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:237)
at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
at py4j.Gateway.invoke(Gateway.java:280)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:128)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:211)
at java.lang.Thread.run(Thread.java:745)
所以看起来它无法解析表格。如何从这里进行测试以确保我已正确连接到数据库?
【问题讨论】:
标签: postgresql jdbc apache-spark pyspark apache-spark-sql