【发布时间】:2011-12-20 11:32:45
【问题描述】:
当我使用 QuartzHelper.getScheduler().checkExists(new JobKey(name,group_name)); 在调度程序中处理作业时,quartz 在 DB 中查找它(为了查看它,我只需删除表并在该方法上得到一个 jdbc 异常)。
但是新作业被添加到调度程序中,没有记录被添加到数据库中。如果我尝试创建一个具有相同名称的新作业,则作业正在运行时 - 会触发异常。例外:
Unable to store Job : 'jobname', because one already exists with this identification.
at org.quartz.simpl.RAMJobStore.storeJob(RAMJobStore.java:277)
很明显是用RAMJobStore代替了JDBC。
问题:我做错了什么,我该怎么做才能让石英在数据库中存储数据?
我有下一个石英配置:
org.quartz.jobStore.class = org.quartz.impl.jdbcjobstore.JobStoreTX
org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.StdJDBCDelegate
org.quartz.jobStore.dataSource = myDS
org.quartz.jobStore.tablePrefix = QRTZ_
org.quartz.jobStore.isClustered = false
org.quartz.dataSource.myDS.driver = com.mysql.jdbc.Driver
org.quartz.dataSource.myDS.URL = jdbc:mysql://127.0.0.1:3306/quartz
org.quartz.dataSource.myDS.user = root
org.quartz.dataSource.myDS.password = qwerty
org.quartz.dataSource.myDS.maxConnections = 10
代码如下:
JobBuilder builder = JobBuilder.newJob(ScriptBaseJob.class);
builder.withIdentity(name, GROUP_NAME);
JobDataMap dataMap = new JobDataMap(params);
builder.usingJobData(dataMap);
builder.requestRecovery(true);
builder.storeDurably(true);
JobDetail jobDetail = builder.build();
SimpleScheduleBuilder scheduleBuilder = SimpleScheduleBuilder.simpleSchedule();
scheduleBuilder.repeatForever();
scheduleBuilder.withIntervalInSeconds(60);
Trigger trigger = null;
try {
trigger = QuartzHelper.getScheduler().getTrigger(new TriggerKey(name, GROUP_NAME));
} catch (Exception e) {
e.printStackTrace();
}
if (trigger==null) {
TriggerBuilder<Trigger> triggerBuilder = TriggerBuilder.newTrigger();
triggerBuilder.withSchedule(scheduleBuilder);
triggerBuilder.withIdentity(name, GROUP_NAME);
trigger = triggerBuilder.build();
}
SchedulerFactory schedFact = new org.quartz.impl.StdSchedulerFactory();
Scheduler sched = schedFact.getScheduler();
sched.start();
sched.scheduleJob(jobDetail, trigger);
【问题讨论】:
标签: java jdbc quartz-scheduler