Capybara：未定义的方法“访问” - 测试已经在规范/功能中

Question

我刚开始使用 RSpec 和 Capybara，但在我的第一次测试中卡住了。 这是我位于spec/features/pages_spec.rb 的测试代码：

require 'rails_helper'

RSpec.describe "Pages", :type => :request do
    describe "About Page" do
        it "should have the content 'About Us'" do
            visit '/pages/about'
            page.should have_content('About Us')
        end
    end
end

运行测试我得到以下错误：

01:06:59 - INFO - Running: spec

F

Failures:

1) Pages About Page should have the content 'About Us'
 Failure/Error: visit '/pages/about'
 NoMethodError:
   undefined method 'visit' for #<RSpec::ExampleGroups::Pages::AboutPage:0x007f975afe7380>
 # ./spec/features/pages_spec.rb:6:in `block (3 levels) in <top (required)>'
 # ./spec/rails_helper.rb:44:in `block (3 levels) in <top (required)>'
 # ./spec/rails_helper.rb:43:in `block (2 levels) in <top (required)>'

Finished in 0.02569 seconds (files took 1.65 seconds to load)

1 example, 1 failure

Failed examples:
rspec ./spec/features/pages_spec.rb:5 # Pages About Page should have the content 'About Us'

我已经搜索了大约一个小时，并且到处都找到了将测试代码从 spec/requests 移动到 spec/features 的解决方案。

我在这里也看到了这个：http://www.rubydoc.info/gems/rspec-rails/file/Capybara.md，大多数解决方案都建议使用它，不建议使用。

# not recommended!
RSpec.configure do |c|
    c.include Capybara::DSL, :file_path => "spec/requests"
end

我不知道如何继续。您的帮助将不胜感激。

Answer 1

要么将 :type => :request 从描述块中取出（它会覆盖从目录位置确定的规范类型），要么将其更改为 :type => :feature。