是否有 python 函数来获取 json 数据的组合？

Question

在下面的json数据中，我需要得到问题和选项的组合（你可以在“选项”中找到它们：[]）。 共有 3 个问题，第一个有 2 个选项，其余两个有 3 个选项，总共应该有 2 x 3 x 3 = 18 种组合。是否有功能可以执行或需要编写循环？ 我需要在 python 中完成。

组合示例：

1. Q1 C1 + Q2 C1 + Q3 C1
2. Q1 C2 + Q2 C1 + Q3 C1
3. Q1 C1 + Q2 C2 + Q3 C1 ...

它们的结果应该类似于这些：

1. 颜色：红色，材质：金属，饰面：哑光
2. 颜色：绿色，材质：金属，饰面：哑光
3. 颜色：红色，材质：橡胶，表面处理：哑光

...

{
    "Success": true,
    "Options": [
        {
            "OptionId": 123,
            "Question": "Color:",
            "Choices": [
                {
                    "ChoiceId": 333,
                    "Choice": "red",
                    "Url": "color/red/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 334,
                    "Choice": "green",
                    "Url": "color/green/",
                    "Exceptions": []
                }
            ]

        },
        {
            "OptionId": 223,
            "Question": "material:",
            "Choices": [
                {
                    "ChoiceId": 223,
                    "Choice": "metal",
                    "Url": "material/metal/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 227,
                    "Choice": "rubber",
                    "Url": "material/rubber/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 229,
                    "Choice": "glass",
                    "Url": "material/glass/",
                    "Exceptions": []
                }
            ]

        },
        {
            "OptionId": 123,
            "Question": "finish:",
            "Choices": [
                {
                    "ChoiceId": 123,
                    "Choice": "matte",
                    "Url": "finish/matte/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 123,
                    "Choice": "glossy",
                    "Url": "finish/glossy/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 123,
                    "Choice": "mix",
                    "Url": "finish/mix/",
                    "Exceptions": []
                }
            ]

        }

    ]
    
}

我有超过 10k 的 json 数据，每个都有不同数量的问题/选择，这只是一个例子。

感谢您的帮助。

Answer 1

有没有python函数可以获取json数据的组合？

据我所知，目前还没有现成的函数直接获取 JSON 数据，但首先将 JSON 加载到 Python 对象中然后组合它们并不难。

import json
o = json.loads("""
{
    "Success": true,
    "Options": [
        {
            "OptionId": 123,
            "Question": "Color:",
            "Choices": [
                {
                    "ChoiceId": 333,
                    "Choice": "red",
                    "Url": "color/red/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 334,
                    "Choice": "green",
                    "Url": "color/green/",
                    "Exceptions": []
                }
            ]

        },
        {
            "OptionId": 223,
            "Question": "material:",
            "Choices": [
                {
                    "ChoiceId": 223,
                    "Choice": "metal",
                    "Url": "material/metal/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 227,
                    "Choice": "rubber",
                    "Url": "material/rubber/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 229,
                    "Choice": "glass",
                    "Url": "material/glass/",
                    "Exceptions": []
                }
            ]

        },
        {
            "OptionId": 123,
            "Question": "finish:",
            "Choices": [
                {
                    "ChoiceId": 123,
                    "Choice": "matte",
                    "Url": "finish/matte/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 123,
                    "Choice": "glossy",
                    "Url": "finish/glossy/",
                    "Exceptions": []
                },
                {
                    "ChoiceId": 123,
                    "Choice": "mix",
                    "Url": "finish/mix/",
                    "Exceptions": []
                }
            ]

        }

    ]
    
}              """)
# now we have the JSON data in the Python object o
questions = [oo["Question"] for oo in o["Options"]]
# now we have the questions = ['Color:', 'material:', 'finish:']
choices = [[c["Choice"] for c in oo["Choices"]] for oo in o["Options"]]
# now we have the choices = [['red', 'green'],
#                            ['metal', 'rubber', 'glass'],
#                            ['matte', 'glossy', 'mix']]

# a well-known recursive algorithm for the cartesian product
# (could instead use itertools.product() as suggested)
def products(cs):
    if cs:
        for c in cs[-1]:
            for p in products(cs[:-1]): yield p+[c]
    else: yield []

cnt = 0
for p in products(choices): # count and print each result in the desired format
    cnt += 1
    print("%d."%cnt, ", ".join([" ".join(qc) for qc in zip(questions, p)]))