【问题标题】:Generate all possible combinations of items生成所有可能的项目组合
【发布时间】:2018-04-12 04:49:00
【问题描述】:

我正在制作一个简单的游戏,我想为玩家的负载做一个展示,并想展示他们拥有的所有可能的项目组合。播放器有三个插槽,每个插槽都有各自的枚举(PlayerSlotPosition)。在 Item 枚举中有多个值,但每个值都需要位于某个 P​​layerSlotPosition 中。

例子:

STICK(PlayerSlotPosition.SLOT_ONE),
STONE(PlayerSlotPosition.SLOT_ONE),
EGG(PlayerSlotPosition.SLOT_TWO),
SHOVEL(PlayerSlotPosition.SLOT_TWO),
PAPER(PlayerSlotPosition.SLOT_THREE),
DIRT(PlayerSlotPosition.SLOT_THREE);

我需要考虑玩家在任何插槽(或多个插槽)中都没有装备任何物品的可能性,这就是我被卡住的地方。如果有人有类似的经验并愿意帮助我,我将不胜感激。感谢阅读

【问题讨论】:

    标签: java combinations permutation


    【解决方案1】:

    这里的关键是I wanted to make a display for the player's load out, and wanted to show every possible combination of items that they have。这大大降低了复杂性,因为您所要做的就是打印出您库存中物品的可能组合。

    public class EnumCombinations {
    
    //Commenting out more than 4 items, loooong printout otherwise
    public static enum ITEM{
        STICK(PlayerSlotPosition.SLOT_ONE),
        STONE(PlayerSlotPosition.SLOT_ONE),
        EGG(PlayerSlotPosition.SLOT_TWO),
        SHOVEL(PlayerSlotPosition.SLOT_TWO);
    //      PAPER(PlayerSlotPosition.SLOT_THREE),
    //      DIRT(PlayerSlotPosition.SLOT_THREE);
        //      DIRT(PlayerSlotPosition.SLOT_THREE);
    
        private ITEM(PlayerSlotPosition pos){
    
        }
    }
    
    public static enum PlayerSlotPosition{
        SLOT_THREE, SLOT_ONE, SLOT_TWO
    
    }
    
    public static List<List<ITEM>> getItemCombinations(List<ITEM> inventory){
        List<ITEM> prefix = new ArrayList<>();
        List<List<ITEM>> container = new ArrayList<>();
        List<ITEM> remainder; 
    
        if(inventory==null){
            System.out.println("Printing all item combinations, no inventory");
            remainder =  new ArrayList<>(Arrays.asList(ITEM.values()));
        }
    
        else {
            remainder = new ArrayList<>(inventory);
        }
        getItemCombinations(prefix, remainder, container);
        return container;
    }
    
    private static void getItemCombinations(List<ITEM> prefix, List<ITEM> remainder, List<List<ITEM>> container){
        int n=remainder.size();
    
        if(remainder.isEmpty()){
            container.add(prefix);
        }
    
        else {
            for(int i=0; i<n; i++) {
                List<ITEM> r = new ArrayList<>();
                List<ITEM> p = new ArrayList<>(prefix);
                p.add(remainder.get(i));
                for(int j=0; j<remainder.size(); j++){
                    if(j==i)
                        continue;
                    r.add(remainder.get(j));
                }
                getItemCombinations(p, r, container);
            }
        }
    }
    
    public static void main (String[] args) {
        System.out.println(getItemCombinations(null)+"\n");
    
        List<ITEM> playerINV = new ArrayList<>();
        playerINV.add(ITEM.STICK);
        playerINV.add(ITEM.STONE);
        playerINV.add(ITEM.EGG);
        System.out.println(getItemCombinations(playerINV));
    
    }
    }
    

    输出:

    Printing all item combinations, no inventory
    [[STICK, STONE, EGG, SHOVEL], [STICK, STONE, SHOVEL, EGG], [STICK, EGG, STONE, SHOVEL], [STICK, EGG, SHOVEL, STONE], [STICK, SHOVEL, STONE, EGG], [STICK, SHOVEL, EGG, STONE], [STONE, STICK, EGG, SHOVEL], [STONE, STICK, SHOVEL, EGG], [STONE, EGG, STICK, SHOVEL], [STONE, EGG, SHOVEL, STICK], [STONE, SHOVEL, STICK, EGG], [STONE, SHOVEL, EGG, STICK], [EGG, STICK, STONE, SHOVEL], [EGG, STICK, SHOVEL, STONE], [EGG, STONE, STICK, SHOVEL], [EGG, STONE, SHOVEL, STICK], [EGG, SHOVEL, STICK, STONE], [EGG, SHOVEL, STONE, STICK], [SHOVEL, STICK, STONE, EGG], [SHOVEL, STICK, EGG, STONE], [SHOVEL, STONE, STICK, EGG], [SHOVEL, STONE, EGG, STICK], [SHOVEL, EGG, STICK, STONE], [SHOVEL, EGG, STONE, STICK]]
    Printing inventory: 
    [[STICK, STONE, EGG], [STICK, EGG, STONE], [STONE, STICK, EGG], [STONE, EGG, STICK], [EGG, STICK, STONE], [EGG, STONE, STICK]]
    

    如果我在您的问题中遗漏了什么,请发表评论,这是一个有趣的问题。

    【讨论】:

    • 我只需要了解玩家在插槽中没有物品的可能性,但这对我来说是一个好的开始。谢谢!
    【解决方案2】:

    查看 powerset 我想这就是你要找的东西

    http://en.wikipedia.org/wiki/Power_set

    (工作电源组) Obtaining a powerset of a set in Java

    【讨论】:

      【解决方案3】:

      我不确定我是否完全理解了这个问题。我猜你并没有真正使用 Object Oriented 方法,因此被 Java 卡住了。

      所以我的建议是对您的对象进行不同的建模。例如:

      为进入特定槽的项目创建接口(例如SlotOneItem, SlotTwoItem),并让项目成为该接口的实现。

      public class Stick implements SlotOneItem {
          ...
      }
      

      对于插槽,您可以使用适当的接口来处理可以存储在该插槽中的项目。例如:

      public class SlotOne {
         public void setItem(SlotOneItem item) {
            ...
         }
      
         public SlotOneItem getItem() {
            ...
         }    
      }
      

      在您的游戏中,您将拥有这两个项目的实例,我猜是每个插槽中的一个,然后可以用适合该插槽的项目填充,或者为空(包含null

      【讨论】:

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