如何合并具有不同 WHERE 和 GROUP BY 子句的两个 SELECT 查询[重复]

Question

我有两个查询如下：

SELECT 
    Actor2Code, 
    COUNT(Actor2Code) AS playermentions 
FROM [events] 
WHERE 
    Year=" + Date + " 
    AND 
    (
        (
            (Actor1CountryCode ='" + mainPlayer1 + "') 
            AND 
            (Actor2CountryCode != '" + mainPlayer1 + "')
        ) 
        OR 
        (
            Actor1CountryCode='" + mainPlayer2 + "' 
            AND 
            Actor2CountryCode !='" + mainPlayer2 + "'
        )
    ) 
GROUP BY Actor2Code;

与

SELECT 
    Actor1Code, 
    COUNT(Actor1Code) AS playermentions 
FROM [events] 
WHERE 
    Year=" + Date + " 
    AND 
    (
        (
            (Actor2CountryCode ='" + mainPlayer1 + "') 
            AND 
            (Actor1CountryCode != '" + mainPlayer1 + "')
        ) 
        OR 
        (
            Actor2CountryCode='" + mainPlayer2 + "' 
            AND 
            Actor1CountryCode !='" + mainPlayer2 + "'
        )
    ) 
GROUP BY Actor1Code

我将结果合并到 c# 中，我有一个演员列表和另一个提及次数列表。如何将这两个查询合二为一，以便我有一个演员列表并且没有重复的演员代码？一些参与者在两个查询的响应中都有不同的提及次数。我想编写一个查询，合并这两个查询的结果并给我一个列表，其中包括不同的 actor1codes 和 actor2codes 以及提及次数（对于重复值，我需要获得提及次数的总和）

Answer 1

这几乎可行，但您必须手动删除重复项。

SELECT ActorCode, playermentions FROM

(SELECT 
    Actor2Code as ActorCode, 
    COUNT(Actor2Code) AS playermentions 
FROM [events] 
WHERE 
    Year=" + Date + " 
    AND 
    (
        (
            (Actor1CountryCode ='" + mainPlayer1 + "') 
            AND 
            (Actor2CountryCode != '" + mainPlayer1 + "')
        ) 
        OR 
        (
            Actor1CountryCode='" + mainPlayer2 + "' 
            AND 
            Actor2CountryCode !='" + mainPlayer2 + "'
        )
    ) 
GROUP BY Actor2Code),
(SELECT 
    Actor1Code as ActorCode, 
    COUNT(Actor1Code) AS playermentions 
FROM [events] 
WHERE 
    Year=" + Date + " 
    AND 
    (
        (
            (Actor2CountryCode ='" + mainPlayer1 + "') 
            AND 
            (Actor1CountryCode != '" + mainPlayer1 + "')
        ) 
        OR 
        (
            Actor2CountryCode='" + mainPlayer2 + "' 
            AND 
            Actor1CountryCode !='" + mainPlayer2 + "'
        )
    ) 
GROUP BY Actor1Code);