尝试 UNNEST 时间戳数组字段，但需要 GROUP BY

Question

我在 BigQuery 表中有一个 TIMESTAMP 类型的重复字段。我正在尝试 UNNEST 这个字段。但是，我必须按顺序对字段进行分组或聚合。我不熟悉 SQL，所以我可以使用一些帮助。代码 sn-p 是更大查询的一部分，当将 subscription.future_renewal_dates 替换为 GENERATE_TIMESTAMP_ARRAY

subscription.future_renewal_dates 是 ARRAY

TIMESTAMP 数组是唯一的（定期订阅），无法使用 GENERATE_TIMESTAMP_ARRAY 生成，因此我必须在上传到 BigQuery 之前生成日期。 UDF 太多了。

SELECT
   subscription.amount AS subscription_amount,
   subscription.status AS subscription_status,
   "1" AS analytic_name,
   ARRAY ( 
   SELECT
      AS STRUCT FORMAT_TIMESTAMP("%x", days) AS type_value, subscription.amount AS analytic_name 
   FROM
      UNNEST(subscription.future_renewal_dates) as days 
   WHERE
      (
         days >= TIMESTAMP("2019-06-05T19:30:02+00:00") 
         AND days <= TIMESTAMP("2019-08-01T03:59:59+00:00") 
      )
) AS forecast 
   FROM
      `mydataset.subscription` AS subscription 
   GROUP BY
      subscription_amount,
      subscription_status,
      analytic_name

无法弄清楚如何成功取消订阅 subscription.future_renewal_dates 而不会出现错误“UNNEST 表达式引用了既不分组也不聚合的订阅.future_renewal_dates”

Answer 1

当您执行 GROUP BY 时 - SELECT 中的所有表达式（除了 GROUP BY 列表中的列）都应与某些聚合函数一起使用 - 您显然没有。因此，您需要决定通过该分组在此处实际尝试实现的目标是什么

以下是我认为您想到的选项 - 尽管它可能会有所不同 - 但至少您对如何解决它有一个想法

SELECT
   subscription.amount AS subscription_amount,
   subscription.status AS subscription_status,
   "1" AS analytic_name,
   ARRAY_CONCAT_AGG( ARRAY ( 
   SELECT
      AS STRUCT FORMAT_TIMESTAMP("%x", days) AS type_value, subscription.amount AS analytic_name 
   FROM
      UNNEST(subscription.future_renewal_dates) as days 
   WHERE
      (
         days >= TIMESTAMP("2019-06-05T19:30:02+00:00") 
         AND days <= TIMESTAMP("2019-08-01T03:59:59+00:00") 
      )
)) AS forecast 
   FROM
      `mydataset.subscription` AS subscription 
   GROUP BY
      subscription_amount,
      subscription_status,
      analytic_name