Xamarin Json 解析答案

【问题标题】：Xamarin Json parsingXamarin Json 解析
【发布时间】：2017-11-24 00:03:24
【问题描述】：

我有一个这样的json：

{"userTweetsList":[{"tweetId":1,"tweetData":"testing uploading from uwp","createdTime":1510822592529,"commentCount":0,"likeCount":1,"flagCount":1,"mediaUrl":"suburl","tweetUser":"geo.thomas","userLiked":true,"userFlagged":true},{"tweetId":2,"tweetData":"Testing tweet","createdTime":1510821224655,"commentCount":0,"likeCount":0,"flagCount":1,"mediaUrl":"suburl","tweetUser":"sreejith.sree","userLiked":false,"userFlagged":true}],"tweetUsersMapList":[{"geo.thomas":{"username":"geo.thomas","name":"geo thomas ","profileImage":null}},{"sreejith.sree":{"username":"sreejith.sree","name":"sreejith sreenivasan","profileImage":null}}],"urlFileserverDynamic":"MyBaseUrl"}

我的模型课：

 public class UserTweetResponse
 {
     public List<UserTweetsList> userTweetsList { get; set; }
 }
 public class UserTweetsList
 {
     public int tweetId { get; set; }
     public string tweetData { get; set; }
     public string createdTime { get; set; }
     public int commentCount { get; set; }
     public int likeCount { get; set; }
     public int flagCount { get; set; }
     public string mediaUrl { get; set; }
     public string tweetUser { get; set; }
     public bool userLiked { get; set; }
     public bool userFlagged { get; set; }
      public bool isMediaUrlNull { get { return string.IsNullOrEmpty(mediaUrl); } }
   }

在我的 cs 文件中，我将 listview 与 userTweetsList 链接起来，我的 listview 名称是 ListView1。

     ListView1.ItemsSource = userTweetResponse.userTweetsList;

我可以使用 {binding} 属性访问 userTweetsList 中的所有数据。

我的问题是我需要根据推文用户值访问并在 ui 中显示名称。假设我需要访问“tweetUser”：“geo.thomas”

{"geo.thomas":{"username":"geo.thomas","name":"geo thomas ","profileImage":null}} inside the tweetUsersMapList, same way for "tweetUser":"sreejith.sree"

我需要数据

{"sreejith.sree":{"username":"sreejith.sree","name":"sreejith sreenivasan","profileImage":null}}

为此，我像这样更改模型：

 public class UserTweetResponse
 {
    public List<UserTweetsList> userTweetsList { get; set; }
    public List<TweetUsersMapList> tweetUsersMapList { get; set; }
 }
 public class UserTweetsList
 {
    public int tweetId { get; set; }
    public string tweetData { get; set; }
    public string createdTime { get; set; }
    public int commentCount { get; set; }
    public int likeCount { get; set; }
    public int flagCount { get; set; }
    public string mediaUrl { get; set; }
    public string tweetUser { get; set; }
    public bool userLiked { get; set; }
    public bool userFlagged { get; set; }
    public bool isMediaUrlNull { get { return string.IsNullOrEmpty(mediaUrl); } }
  }

 public class TweetUsersMapList
 {
    public string username { get; set; }
    public string name { get; set; }
    public string profileImage { get; set; }
 }

但我不知道如何做剩下的部分。如何将列表视图与 tweetUsersMapList 链接？根据 tweetUser 名称，我如何选择名称并在 ui 中显示？是否可以解析这种类型的复杂json？任何人，请提出解决方案提前谢谢...

【问题讨论】：

标签： json xamarin.forms

【解决方案1】：

public class UserTweetsList
{
    public int tweetId { get; set; }
    public string tweetData { get; set; }
    public object createdTime { get; set; }
    public int commentCount { get; set; }
    public int likeCount { get; set; }
    public int flagCount { get; set; }
    public string mediaUrl { get; set; }
    public string tweetUser { get; set; }
    public bool userLiked { get; set; }
    public bool userFlagged { get; set; }
}

public class GeoThomas
{
    public string username { get; set; }
    public string name { get; set; }
    public object profileImage { get; set; }
}

public class SreejithSree
{
    public string username { get; set; }
    public string name { get; set; }
    public object profileImage { get; set; }
}

public class TweetUsersMapList
{
    public GeoThomas __invalid_name__geo.thomas { get; set; }
    public SreejithSree __invalid_name__sreejith.sree { get; set; }
}

public class RootObject
{
    public List<UserTweetsList> userTweetsList { get; set; }
    public List<TweetUsersMapList> tweetUsersMapList { get; set; }
    public string urlFileserverDynamic { get; set; }
}

我已经使用Json2csharp 来生成这些类...

【讨论】：