【发布时间】:2015-04-16 18:17:15
【问题描述】:
我正在尝试制作一个带有四个按钮的问答游戏,问题存储在一个数组中。这些字母应该一次打印出一个,并且在显示前 3 个索引之后,只有当按下屏幕上的按钮时才会显示下一个索引。
到目前为止,我似乎只能显示前 3 个索引,但我不确定如何让按钮触发数组中的下一个问题来显示。
我的代码是:
public GameObject button1;
public GameObject button2;
public GameObject button3;
public GameObject button4;
public float letterPause = 0.05f;
public float sentencePause = 2.0f;
string[] strArray = new string[13];
int i;
int count = 3;
int score;
bool nextQuestion = false;
void Start () {
strArray[0] = "Hello and welcome!";
strArray[1] = "This 11 question quiz is going to test your knowledge";
strArray[2] = "Question 1";
strArray[3] = "Question 2";
strArray[4] = "Question 3";
strArray[5] = "Question 4";
strArray[6] = "Question 5";
strArray[7] = "Question 6";
strArray[8] = "Question 7";
strArray[9] = "Question 8";
strArray[10] = "Question 9";
strArray[11] = "Question 10";
strArray[12] = "Question 11";
StartCoroutine (TypeText ());
}
IEnumerator TypeText () {
for (i = 0; i < count; i++) {
foreach (char letter in strArray[i].ToCharArray()) {
gameObject.GetComponent<Text> ().text += letter;
yield return new WaitForSeconds (letterPause);
}
if (i != count - 1) {
yield return new WaitForSeconds (sentencePause);
gameObject.GetComponent<Text> ().text = "";
}
}
StartCoroutine (TypeText2 ());
}
IEnumerator TypeText2 () {
while (nextQuestion == true) {
for (i = 3; i < strArray.Length; i++) {
foreach (char letter in strArray[i].ToCharArray()) {
gameObject.GetComponent<Text> ().text += letter;
yield return new WaitForSeconds (letterPause);
}
gameObject.GetComponent<Text> ().text = "";
}
}
}
public void OnClickButton1() {
button1.GetComponentInChildren<Text> ().text = "";
button2.GetComponentInChildren<Text> ().text = "";
button3.GetComponentInChildren<Text> ().text = "";
button4.GetComponentInChildren<Text> ().text = "";
nextQuestion = true;
}
public void OnClickButton2() {
button1.GetComponentInChildren<Text> ().text = "";
button2.GetComponentInChildren<Text> ().text = "";
button3.GetComponentInChildren<Text> ().text = "";
button4.GetComponentInChildren<Text> ().text = "";
nextQuestion = true;
}
public void OnClickButton3() {
button1.GetComponentInChildren<Text> ().text = "";
button2.GetComponentInChildren<Text> ().text = "";
button3.GetComponentInChildren<Text> ().text = "";
button4.GetComponentInChildren<Text> ().text = "";
nextQuestion = true;
}
public void OnClickButton4() {
button1.GetComponentInChildren<Text> ().text = "";
button2.GetComponentInChildren<Text> ().text = "";
button3.GetComponentInChildren<Text> ().text = "";
button4.GetComponentInChildren<Text> ().text = "";
nextQuestion = true;
}
【问题讨论】:
-
您使用什么 GUI 系统来创建按钮?如果是新的 Unity UI 系统,只需在这个单一行为上创建一个公共方法并将其链接到按钮的属性中。
-
我正在使用新的 Unity UI 系统,但是当您说将其链接到按钮的属性时,我不确定您的意思。