在Dataweave中拆分字符串后如何从数组中获取第一个值？答案

【问题标题】：How to get the first value from an Array after split String in Data weave?在Dataweave中拆分字符串后如何从数组中获取第一个值？
【发布时间】：2021-02-19 10:01:08
【问题描述】：

我试图在拆分字符串后比较字符串数组中的第一个值。但是我的子函数抛出错误说它接收一个数组，我做错了什么。

fun getErrorList() =
compareAddress(loanData.loan.propertyAddress,payload.propertyAddress)
fun compareAddress(loanpropertyAddress, inputPropertyAddress) =
if(null != loanpropertyAddress and null != inputPropertyAddress)
getAddr1 (loanpropertyAddress splitBy(" "))[0]
==
getAddr1 (inputPropertyAddress splitBy(" "))[0]
else
null

fun getAddr1(addr1) =
addr1 replace "#" with ("")

【问题讨论】：

标签： dataweave mule4

【解决方案1】：

问题在于您如何调用 getAddr1 函数。在您提供的 DataWeave 表达式中，您将字符串数组而不是字符串传递给 getAddr1 函数：

...
getAddr1(
    loadpropertyAddress splitBy(" ") // splitBy returns an array of strings
)[0] // here, you're trying to get the first element of the value returned by getAddr1
...

我假设您在删除“#”字符后尝试比较贷款的第一部分和输入的财产地址。如果我的理解是正确的，那么您可以对您的功能进行以下更改：

...
getAddr1(
    loadpropertyAddress splitBy(" ")[0] // get the first element of the string array returned by the splitBy function
) // removed array item selector ([0])
...

修改后，您的 DataWeave 表达式应如下所示：

fun getErrorList() =
compareAddress(loanData.loan.propertyAddress,payload.propertyAddress)
fun compareAddress(loanpropertyAddress, inputPropertyAddress) =
if(null != loanpropertyAddress and null != inputPropertyAddress)
getAddr1 (loanpropertyAddress splitBy(" ")[0])
==
getAddr1 (inputPropertyAddress splitBy(" ")[0])
else
null

fun getAddr1(addr1) =
addr1 replace "#" with ("")

【讨论】：