【发布时间】:2017-11-18 04:12:26
【问题描述】:
在我的聊天程序中,我需要将文件发送给其他用户,但我遇到了问题。 当我尝试发送文件时,Visual Studio 给我一个异常,不支持给定路径的格式;
private void button3_Click(object sender, EventArgs e)
{
Stream myStream = null;
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "A:\\";
openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
openFileDialog1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyComputer).ToString();
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null)
{
using (myStream)
{
byte[] bytes = File.ReadAllBytes(openFileDialog1.ToString());
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error:"+ ex.Message);
}
}
}
请帮忙。
【问题讨论】:
-
openFileDialog1.ToString()不会返回所选文件的路径 - 它会返回System.Windows.Forms.OpenDialog(对象的类型)。你想要openDialog1.FileName。 -
获取路径文件后抛出异常
标签: c# .net chat notsupportedexception