Jess 模式匹配规则上的“非”条件

Question

我在玩 jess。我想制定不使用'~'的规则。

这是我的代码。

(clear)
(reset)

(deftemplate person
    (slot name)
    (slot eyes)
    (slot hair))

(defrule person-without-brown-hair
    (person (name ?name) (hair ?hair&:(not brown)))
=>
    (printout t ?name " does not have brown hair." crlf))

(assert (person (name "Jeon") (eyes green) (hair brown)))
(assert (person (name "Park") (eyes blue) (hair red)))

(run)

我所期望的是可变的？头发不是棕色的。

Answer 1

请注意，函数(not ...) 否定了它的参数。 TRUE 为真，FALSE 为假，任何其他符号为真。

要测试一个槽值是否等于某个值，请使用(eq ...) 或(neq ...) 或(= ...) 或(<> ...)。

(defrule person-without-brown-hair
    (person (name ?name) (hair ?hair&:(neq ?hair brown)))
=>
    (printout t ?name " does not have brown hair." crlf))

结果：

Park does not have brown hair.
1

直接匹配当然更好。