UIButton 在工作前需要点击 3 次？迅速

Question

我有一个如图所示的按钮，当用户首先按下它时，它应该会更改图像并且用户现在正在关注此配置文件。但是，当用户第一次按下按钮时，它什么也不做，第二次点击它就可以工作。如何在第一次点击时完成这项工作？

编辑清理后的代码此代码需要点击两次按钮才能工作。双击它会跟随或取消关注用户并更新图像。但就像我说的那样，它需要点击两次。

 @IBAction func favButton(sender: UIButton) {

    buttonPressed = !buttonPressed


            if buttonPressed == true {

                let followedObjectId = userToShowDetail?["name"] as? String

                if isFollowing[followedObjectId!] == true {


                }

            } else  {

                let followedObjectId = userToShowDetail?["name"] as? String

                if isFollowing[followedObjectId!] == false {

                    isFollowing[followedObjectId!] = true
                    sender.setImage(UIImage(named: "fave_on@2x.png"), forState: UIControlState.Normal)


                    print("follow")

                    let following = PFObject(className: "Followers")
                    following["following"] = userToShowDetail?["name"] as? String
                    following["follower"] = PFUser.currentUser()?.objectId
                    favLabel.text = "Favourite Jammer"

                    following.saveInBackground()

                } else {

                    if buttonPressed != true {

                        isFollowing[followedObjectId!] = false
                        print("notFollow")
                        sender.setImage(UIImage(named: "fave_off@2x.png"), forState: UIControlState.Normal)
                        favLabel.text = "Add to favourites?"

                    }

                }
            }

此代码在视觉上修复了它，但它不再在幕后工作。 按钮更改图像并打印关注和取消关注日志，但它不会取消关注用户并添加关注用户访问我的数据两次。

        buttonPressed = !buttonPressed

    if buttonPressed == true {

        let followedObjectId = userToShowDetail?["name"] as? String

        isFollowing[followedObjectId!] = true

        sender.setImage(UIImage(named: "fave_on@2x.png"), forState: UIControlState.Normal)
        print("follow")

        let following = PFObject(className: "Followers")
        following["following"] = userToShowDetail?["name"] as? String
        following["follower"] = PFUser.currentUser()?.objectId
        favLabel.text = "Favourite Jammer"

        following.saveInBackground()

    } else {

        if buttonPressed != true {
            let followedObjectId = userToShowDetail?["name"] as? String

            isFollowing[followedObjectId!] = false
            print("notFollow")
            sender.setImage(UIImage(named: "fave_off@2x.png"), forState: UIControlState.Normal)
            favLabel.text = "Add to favourites?"

        } // !=true
    } // else

} // uibutton

Answer 1

代码非常混乱，我不建议这样处理......正在发生的查询太多，并且该按钮中的一般情况太多......

但是，任何查询（您要在应用程序中访问和修改的数据）都应该在 viewDidLoad（或类似方法）中，以便在按下按钮之前值就在那里。这些值应存储在数组中。当按下按钮时，您将已经可以访问这些值，并且将来以不同的方法修改它们会更容易。

这需要缩短。

但是，假设您仍然想这样做，按钮逻辑需要分解为功能。

从该查询中创建一个函数，然后在按钮中引用它。发生了太多事情 + 你在错误的地方调用了按钮。

这是一个非常粗略的例子：

您的按钮应该看起来像 这样：

  @IBAction func favButton(sender: UIButton) {

    buttonPressed = !buttonPressed

    if buttonPressed == true {

        let followedObjectId = userToShowDetail?["name"] as? String

        if isFollowing[followedObjectId!] == true {

            //something needs to happen here?

        }

        updateImage()

    } else  {


      followersUpdate()

    }

   }


      //Your functions below the button: 

 func followersUpdate() {

    let followedObjectId = userToShowDetail?["name"] as? String

    if isFollowing[followedObjectId!] == false {

    isFollowing[followedObjectId!] = true
    sender.setImage(UIImage(named: "fave_on@2x.png"), forState: UIControlState.Normal)

    print("follow")

    let following = PFObject(className: "Followers")
    following["following"] = userToShowDetail?["name"] as? String
    following["follower"] = PFUser.currentUser()?.objectId
    favLabel.text = "Favourite Jammer"

    following.saveInBackground()

    } else {

    }

}

func updateImage() {
        if buttonPressed != true {

            isFollowing[followedObjectId!] = false
            print("notFollow")
            sender.setImage(UIImage(named: "fave_off@2x.png"), forState: UIControlState.Normal)
            favLabel.text = "Add to favourites?"


            let query = PFQuery(className: "Followers")

            query.whereKey("follower", equalTo: PFUser.currentUser()!.objectId!)
            query.whereKey("following", equalTo: (userToShowDetail?["name"] as? String)!)

            query.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in

                if let objects = objects {

                    for object in objects {

                        object.deleteInBackground()

                    }
                }

            })

        }

    }

    //Your viewDidLoad() initial query to parse:  


 override func viewDidLoad() {
    super.viewDidLoad()

    let query = PFUser.query()

    query?.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in

        if let users = objects {

            for object in users {

                if let user = object as? PFUser {

                    if user.objectId! != PFUser.currentUser()?.objectId {

                        self.usernames.append(user.username!)
                        self.userids.append(user.objectId!)

                        let query = PFQuery(className: "Followers")

                        query.whereKey("follower", equalTo: (PFUser.currentUser()!.objectId)!)
                        query.whereKey("following", equalTo: user.objectId!)

                        query.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in

                            if let objects = objects {

                                if objects.count > 0 {

                                    self.isFollowing[user.objectId!] = true

                                } else {

                                    self.isFollowing[user.objectId!] = false

                                }
                            }

                            if self.isFollowing.count == self.usernames.count {

                            }
                        })
                    }
                }

            }
        }
    })
}

正如我所提到的，这是一个粗略的示例，可以让您了解应该做什么（即使我认为查询和服务器来回发送是 1）多余的，2）不需要，3）会你的应用程序变慢了。）

如果您像这样分解它并且按钮中的内容较少，则图像应该更新。您将不得不解决这个问题并修改代码/使其更短。

如果您有更多问题，请告诉我，我们很乐意为您提供帮助。