如何按每个单独的单词和该单词组的另一列中的总和值进行分组？答案

【问题标题】：How to group by each separate word and sum value in another column for that word group?如何按每个单独的单词和该单词组的另一列中的总和值进行分组？
【发布时间】：2017-04-27 19:24:48
【问题描述】：

假设我有一个包含如下数据的表：

keyword          times_phrase_searched
-------          ---------------------
open windows     1000
closed windows   750
open doors       350
closed doors     250
nice window      100
nice windows     50
ugly doors       25

我需要什么样的 SQL 查询才能分别对每个单词进行分组并将该单词所在词组的搜索量相加。因此，对于示例数据，预期结果将是：

word             times_word_in_searches
----             ----------------------
windows          1800
open             1350
closed           1000
doors            625
nice             150
window           100
ugly             25

【问题讨论】：

标签： mysql sql

【解决方案1】：

如果您没有数字表，请创建一个（查看方法here）。然后你可以使用这个查询来获取字数：

select SUBSTRING_INDEX(SUBSTRING_INDEX(words.keyword, ' ', numbers.n), ' ', -1) word, 
       SUM(words.times_phrase_searched) times_word_in_searches
from numbers 
inner join words on CHAR_LENGTH(words.keyword) - CHAR_LENGTH(REPLACE(words.keyword, ' ', '')) >= numbers.n - 1
group by word
order by sum(words.times_phrase_searched) desc;

这会拆分您的关键字列，以便您将每个单独的关键字放在自己的行中。那么group和sum就很简单了。

DEMO

【讨论】：

【解决方案2】：

试试这个...

DECLARE @temp TABLE 
  ( 
     keyword VARCHAR(max), 
     times   INT 
  ) 

INSERT INTO @temp 
VALUES      ('open windows', 
             1000 ), 
            ('closed windows', 
             750 ), 
            ('open doors', 
             350 ), 
            ('closed doors', 
             250 ), 
            ('nice window', 
             100 ), 
            ('nice windows', 
             50 ), 
            ('ugly doors', 
             25 ) 

DECLARE @allValues VARCHAR(max) = (SELECT Stuff((SELECT 
                                          ',' + Replace(p2.keyword, ' ', 
                                          ',') 
                 FROM   @temp p2 
                 ORDER  BY p2.keyword 
                 FOR xml path(''), type).value('.', 'varchar(max)'), 1, 1, '')) 


-- find distinct words 
SELECT DISTINCT t.element, 
                (SELECT Sum(k.times) 
                 FROM   @temp k 
                 WHERE  k.keyword LIKE '%' + t.element + '%') 
FROM   dbo.Func_split(@allValues, ',') t

函数Func_split（信用：https://stackoverflow.com/a/21428746/710925）

CREATE FUNCTION [dbo].[func_Split] 
    (   
    @DelimitedString    varchar(8000),
    @Delimiter              varchar(100) 
    )
RETURNS @tblArray TABLE
    (
    ElementID   int IDENTITY(1,1),  -- Array index
    Element     varchar(1000)               -- Array element contents
    )
AS
BEGIN

    -- Local Variable Declarations
    -- ---------------------------
    DECLARE @Index      smallint,
                    @Start      smallint,
                    @DelSize    smallint

    SET @DelSize = LEN(@Delimiter)

    -- Loop through source string and add elements to destination table array
    -- ----------------------------------------------------------------------
    WHILE LEN(@DelimitedString) > 0
    BEGIN

        SET @Index = CHARINDEX(@Delimiter, @DelimitedString)

        IF @Index = 0
            BEGIN

                INSERT INTO
                    @tblArray 
                    (Element)
                VALUES
                    (LTRIM(RTRIM(@DelimitedString)))

                BREAK
            END
        ELSE
            BEGIN

                INSERT INTO
                    @tblArray 
                    (Element)
                VALUES
                    (LTRIM(RTRIM(SUBSTRING(@DelimitedString, 1,@Index - 1))))

                SET @Start = @Index + @DelSize
                SET @DelimitedString = SUBSTRING(@DelimitedString, @Start , LEN(@DelimitedString) - @Start + 1)

            END
    END

    RETURN
END

【讨论】：

【解决方案3】：

;

 with tmp(keyword, times_phrase_searched) as(
select times_phrase_searched, LEFT((keyword, CHARINDEX(' ',(keyword+' ')-1),
 STUFF(Data, 1, CHARINDEX(' ',keyword+' '), '')
from TestData
Union ALL
select times_phrase_searched, LEFT((keyword, CHARINDEX(' ',(keyword+' ')-1),
 STUFF(Data, 1, CHARINDEX(' ',keyword+' '), '')
from Test
Where Data >'')
SELECT
   keyword,
   SUM(times_phrase_searched) AS times_phrase_searched   
FROM tmp
GROUP BY keyword;

我不确定，但请检查一下...

【讨论】：

这不是 MySQL。