【发布时间】:2018-02-23 04:00:55
【问题描述】:
我正在尝试使用 DateDiff 函数更新 DaysInPeriod,基于 EFFECTIVESTARTDATE 字段中的更改。
这是我的 DLL:
DROP TABLE Reporting_Table
CREATE TABLE Reporting_Table (
Credit_Line_NO Varchar(10),
CURRENCY VARCHAR(3),
AMOUNT INT,
StartDate DATE,
EFFECTIVESTARTDATE DATE,
EXPIRY_DATE Date,
FREQUENCY INT,
CO_CODE VARCHAR(10),
AsOfDate Date,
SOURCEID_REVISED VARCHAR(255),
PID VARCHAR(5),
DaysInPeriod INT
)
INSERT INTO Reporting_Table(CREDIT_LINE_NO,CURRENCY,AMOUNT,STARTDATE,EFFECTIVESTARTDATE,EXPIRY_DATE,FREQUENCY,CO_CODE,ASOFDATE,SourceID_Revised,PID,DaysInPeriod)
VALUES
('1026321','USD','16875','9/30/2017','9/30/2017','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','12/31/2017','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','3/31/2018','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','6/30/2018','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','9/30/2018','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','12/31/2018','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','3/31/2019','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026321','USD','16875','9/30/2017','6/30/2019','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026329','USD','16875','9/30/2017','9/30/2017','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026329','USD','16875','9/30/2017','12/31/2017','9/30/2019','8','US0010001','7/31/2017','','',''),
('1026329','USD','16875','9/30/2017','3/31/2018','9/30/2019','8','US0010001','7/31/2017','','','')
选择 * 来自 Reporting_Table
Select *
From Reporting_Table
我有这个 SQL:
with cte as
(
select *, rn = row_number() over (partition by Credit_Line_NO,ASOFDATE order by ASOFDATE)
from Reporting_Table
)
Select *
From cte
基本上,当 rn=1 时,DaysInPeriod = 90,然后每下一个 rn,它应该增加 DateDiff(days,rn-1,rn)。它应该根据 Credit_Line_NO 和 ASOFDATE 的变化进行重置,所以我使用的是:
partition by Credit_Line_NO,ASOFDATE
这是我想要实现的示例。
我使用的是 SQL Server 2008,因此无法使用 Lead/Lag 函数。我把下面的 SQL 放在一起,但它没有执行。
SELECT T1.CREDIT_LINE_NO,
T1.CURRENCY,
T1.AMOUNT,
T1.STARTDATE,
T1.EFFECTIVESTARTDATE,
T1.EXPIRY_DATE,
T1.FREQUENCY,
T1.CO_CODE,
T1.AsOfDate
MIN(T2.EFFECTIVESTARTDATE) AS Date2,
DATEDIFF("D", T1.EFFECTIVESTARTDATE, MIN(T2.EFFECTIVESTARTDATE)) AS DaysDiff
FROM Reporting_Table T1
LEFT JOIN Reporting_Table T2
ON T1.CREDIT_LINE_NO = T2.CREDIT_LINE_NO
AND T2.EFFECTIVESTARTDATE > T1.EFFECTIVESTARTDATE
GROUP BY T1.CREDIT_LINE_NO,
T1.CURRENCY,
T1.AMOUNT,
T1.STARTDATE,
T1.EFFECTIVESTARTDATE,
T1.EXPIRY_DATE,
T1.FREQUENCY,
T1.CO_CODE,
T1.AsOfDate
最后,我想运行一个 UPDATE 查询或 SELECT * INTO NEW_TABLE 查询。
【问题讨论】:
-
从不执行的查询中得到什么错误信息?
-
我不清楚
-
您的查询失败,因为第 9 行“T1.AsOfDate”没有逗号。
-
按列分区并按列排序是没有意义的。
标签: sql-server sql-server-2008 tsql