将列总和到 SQL 中的当前行？答案

【问题标题】：Sum column up to the current row in SQL?将列总和到 SQL 中的当前行？
【发布时间】：2015-04-17 18:00:09
【问题描述】：

我正在尝试将一列汇总到当前行（在 SQL Server 中）。我该怎么做？

select t1.CounterTime,
       t1.StartTime,
       t1.EndTime,
       isNull(t1.value, 0) as value1,

       -- How do I make Total1 the sum of t1.value over all previous rows?
       sum( isNull(t1.value, 0) ) over (partition by t1.CounterTime order by t1.CounterTime) as Total1

from   SomeTable t1
order by t1.CounterTime

但是我弄错了partition by...

╔═══╦═════════════════════════╦═════════════════════════╦═════════════════════════╦════════╦════════╗
║   ║      CounterTime        ║        StartTime        ║         EndTime         ║ value1 ║ Total1 ║
╠═══╬═════════════════════════╬═════════════════════════╬═════════════════════════╬════════╬════════╣
║ 1 ║ 2015-03-17 12:00:00.000 ║ 2015-03-17 00:00:00.000 ║ 2015-03-18 00:00:00.000 ║     0  ║     0  ║
║ 2 ║ 2015-03-18 12:00:00.000 ║ 2015-03-18 00:00:00.000 ║ 2015-03-19 00:00:00.000 ║     0  ║     0  ║
║ 3 ║ 2015-03-19 12:00:00.000 ║ 2015-03-19 00:00:00.000 ║ 2015-03-20 00:00:00.000 ║   422  ║   422  ║
║ 4 ║ 2015-03-20 12:00:00.000 ║ 2015-03-20 00:00:00.000 ║ 2015-03-21 00:00:00.000 ║   989  ║   989  ║
║ 5 ║ 2015-03-21 12:00:00.000 ║ 2015-03-21 00:00:00.000 ║ 2015-03-22 00:00:00.000 ║  1162  ║  1162  ║
║ 6 ║ 2015-03-22 12:00:00.000 ║ 2015-03-22 00:00:00.000 ║ 2015-03-23 00:00:00.000 ║   524  ║   524  ║
╚═══╩═════════════════════════╩═════════════════════════╩═════════════════════════╩════════╩════════╝

应该是：

╔════════╗
║ Total1 ║
╠════════╣
║     0  ║
║     0  ║
║   422  ║
║  1411  ║
║  2573  ║
║  3097  ║
╚════════╝

【问题讨论】：

您使用的是哪个版本的SQL Server？
也许使用相关子查询来做 SUM？
这可能非常相关，如果不是重复的话：stackoverflow.com/questions/860966/…
如果你想要之前所有行的总和，只需删除 partition by t1.CounterTime 并保留 order by t1.CounterTime

标签： sql sql-server sum partitioning

【解决方案1】：

试试这个
删除“partition by”只使用“order by”

select t1.CounterTime,
           t1.StartTime,
           t1.EndTime,
           isNull(t1.value, 0) as value1,

           -- How do I make Total1 the sum of t1.value over all previous rows?
           sum( isNull(t1.value, 0) ) over (order by t1.CounterTime) as Total1

    from   SomeTable t1
    order by t1.CounterTime

【讨论】：

【解决方案2】：

这里是一个计算运行总数的示例

declare @t table (id int,val int)
insert into @t(id,val)values (1,0),(2,0),(3,411),(4,989),(5,1162),(6,524)

SELECT ID, val, RunningTotal = val + COALESCE(
(
  SELECT SUM(val)
    FROM @t AS i
    WHERE i.ID < o.ID), 0
)
FROM @t AS o
ORDER BY ID;

IN Sql 2012

SELECT ID, val, 
  RunningTotal = SUM(val) OVER (ORDER BY TID ROWS UNBOUNDED PRECEDING)
FROM @t
ORDER BY TID;

可以在您的查询中使用相同的代码

select t1.CounterTime,
           t1.StartTime,
           t1.EndTime,
           isNull(t1.value, 0) as value1,
           RunningTotal = t1.value + COALESCE(
(
  SELECT SUM(value)
    FROM SomeTable AS i
    WHERE i.CounterTime < o.CounterTime), 0
)

    from   SomeTable t1
    order by t1.CounterTime

【讨论】：