【发布时间】:2014-06-04 22:36:40
【问题描述】:
我有一个 SQL 查询,我在其中提取员工考勤卡信息。它提取姓名、工资单 ID、位置、正常工作时间和加班时间。但是,我无法弄清楚如何使用 case 和 Sum 正确地舍入正常和加班时间。下面是我的代码,不是四舍五入。
SELECT Employee_Tb.First_Name + ' ' + Employee_Tb.Last_Name AS Name, Employee_Tb.Home_Store_Id, Employee_Tb.Payroll_Id,
CASE WHEN SUM(Payroll_Hours_Tb.Hours_Worked) > 40.0 THEN 40.0 ELSE Round(SUM(Payroll_Hours_Tb.Hours_Worked), 2) END AS RegHours,
CASE WHEN SUM(Payroll_Hours_Tb.Hours_Worked) > 40.0 THEN Round(SUM(Payroll_Hours_Tb.Hours_Worked), 2) - 40.0 ELSE 0.0 END AS OTHours
FROM Employee_Tb INNER JOIN
Payroll_Hours_Tb ON Employee_Tb.Employee_Id = Payroll_Hours_Tb.Employee_Id
WHERE (Payroll_Hours_Tb.Work_Date BETWEEN @startdate AND @enddate)
GROUP BY Employee_Tb.Payroll_Id, Employee_Tb.First_Name, Employee_Tb.Last_Name, Employee_Tb.Home_Store_Id
ORDER BY Employee_Tb.Home_Store_Id
结果示例如下:常规时间“21.91999999”
应该是:“21.92”
【问题讨论】:
-
将结果转换为
decimal(10, 2)或您喜欢的任何格式。 -
这太完美了。如果您想发布它,我会接受它作为答案。谢谢!
标签: sql sql-server