如何用一条语句从 Oracle 数据库中选择所有存储过程？

Question

我想在 Oracle 数据库中查看所有fooUser 拥有的存储过程实现。

通过使用rownum，我可以为dba_objects 表中的第一个过程执行此操作，但fooUser 拥有的dba_objects 表中有许多过程。

我不想编写存储过程来实现这一点，我想用一条 SQL 语句来做到这一点。

查询以获取第一个存储过程实现：

SELECT 
    line, text
FROM 
    dba_source
WHERE
    name = (SELECT object_name 
            FROM dba_objects 
            WHERE object_type = 'PROCEDURE' 
              AND owner = 'fooUser' AND rownum = 1) 
    AND type = 'PROCEDURE'
ORDER BY 
    line

Answer 1

要获取程序源，您可以使用dbms_metadata.get_ddl

在此处查看文档dbms_metadata

例如，下面的脚本会为您返回所有者为 usr1 的每个过程的过程列表和源

select object_name
     , dbms_metadata.get_ddl(object_type,object_name) from dba_procedures
  where owner = 'USR1'
    and object_type = 'PROCEDURE'

或

如果您只需要所有程序的逐行文本

SELECT line, text
FROM dba_source
WHERE owner = 'SCM'
  AND type = 'PROCEDURE'
ORDER BY name, line

Answer 2

试试这个：

SELECT line, text
FROM dba_source
WHERE owner = ?
  AND name = ?
  AND type = 'PROCEDURE'
ORDER BY line

更新 #1：

SELECT line, text
FROM dba_source
WHERE owner = 'foouser'
  AND type = 'PROCEDURE'
ORDER BY line

更新 #2：

   SELECT line, text, name
    FROM dba_source
    WHERE owner = 'foouser'
      AND type = 'PROCEDURE'
    ORDER BY name, line