【问题标题】:What the error when I close the dialog关闭对话框时出现什么错误
【发布时间】:2014-07-29 10:15:22
【问题描述】:

我刚刚学习 PyQt,我有一个似乎可以正常工作的小应用程序,我点击对话框右上角的 X 将其关闭。当我这样做并返回控制台时,我看到异常已引发如下:

To exit: use 'exit', 'quit', or Ctrl-D.
An exception has occurred, use %tb to see the full traceback.

SystemExit: 0


In [2]: %tb
Traceback (most recent call last):

  File "<ipython-input-1-4524246fa84a>", line 1, in <module>
    runfile('C:/Users/21025/simpleAdder.pyw', wdir='C:/Users/21025')

  File "C:\Users\21035\AppData\Local\Continuum\Anaconda\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 586, in runfile
    execfile(filename, namespace)

  File "C:/Users/21035/simpleAdder.pyw", line 81, in <module>
    sys.exit(app.exec_())

SystemExit: 0

我做错了什么?应用代码如下:

from PyQt4 import QtCore, QtGui

try:
    _fromUtf8 = QtCore.QString.fromUtf8
except AttributeError:
    def _fromUtf8(s):
        return s

try:
    _encoding = QtGui.QApplication.UnicodeUTF8
    def _translate(context, text, disambig):
        return QtGui.QApplication.translate(context, text, disambig, _encoding)
except AttributeError:
    def _translate(context, text, disambig):
        return QtGui.QApplication.translate(context, text, disambig)

class Ui_Dialog(object):
    def setupUi(self, Dialog):
        Dialog.setObjectName(_fromUtf8("Dialog"))
        Dialog.resize(673, 565)
        self.v1Input = QtGui.QLineEdit(Dialog)
        self.v1Input.setGeometry(QtCore.QRect(50, 70, 71, 20))
        self.v1Input.setObjectName(_fromUtf8("v1Input"))
        self.v2Input = QtGui.QLineEdit(Dialog)
        self.v2Input.setGeometry(QtCore.QRect(150, 70, 71, 20))
        self.v2Input.setObjectName(_fromUtf8("v2Input"))
        self.v3Input = QtGui.QLineEdit(Dialog)
        self.v3Input.setGeometry(QtCore.QRect(250, 70, 71, 20))
        self.v3Input.setObjectName(_fromUtf8("v3Input"))
        self.calc_result = QtGui.QLineEdit(Dialog)
        self.calc_result.setGeometry(QtCore.QRect(420, 70, 113, 20))
        self.calc_result.setObjectName(_fromUtf8("calc_result"))
        self.label = QtGui.QLabel(Dialog)
        self.label.setGeometry(QtCore.QRect(60, 50, 46, 13))
        self.label.setObjectName(_fromUtf8("label"))
        self.label_2 = QtGui.QLabel(Dialog)
        self.label_2.setGeometry(QtCore.QRect(160, 50, 46, 13))
        self.label_2.setObjectName(_fromUtf8("label_2"))
        self.label_3 = QtGui.QLabel(Dialog)
        self.label_3.setGeometry(QtCore.QRect(260, 50, 46, 13))
        self.label_3.setObjectName(_fromUtf8("label_3"))
        self.label_4 = QtGui.QLabel(Dialog)
        self.label_4.setGeometry(QtCore.QRect(450, 50, 46, 13))
        self.label_4.setObjectName(_fromUtf8("label_4"))
        self.pushButton = QtGui.QPushButton(Dialog)
        self.pushButton.setGeometry(QtCore.QRect(200, 230, 75, 23))
        self.pushButton.setObjectName(_fromUtf8("pushButton"))

        self.retranslateUi(Dialog)
        QtCore.QObject.connect(self.pushButton, QtCore.SIGNAL(_fromUtf8("clicked()")), self.v1Input.clear)
        QtCore.QObject.connect(self.pushButton, QtCore.SIGNAL(_fromUtf8("clicked()")), self.v2Input.clear)
        QtCore.QObject.connect(self.pushButton, QtCore.SIGNAL(_fromUtf8("clicked()")), self.v3Input.clear)
        QtCore.QMetaObject.connectSlotsByName(Dialog)


    def retranslateUi(self, Dialog):
        Dialog.setWindowTitle(_translate("Dialog", "Dialog", None))
        self.label.setText(_translate("Dialog", "Val 1", None))
        self.label_2.setText(_translate("Dialog", "Val 2", None))
        self.label_3.setText(_translate("Dialog", "Val 3", None))
        self.label_4.setText(_translate("Dialog", "Result", None))
        self.pushButton.setText(_translate("Dialog", "Clear Inputs", None))       


if __name__ == "__main__":
    import sys
    app = QtGui.QApplication(sys.argv)
    Dialog = QtGui.QDialog()
    ui = Ui_Dialog()
    ui.setupUi(Dialog)
    Dialog.show()
    sys.exit(app.exec_())

【问题讨论】:

    标签: python pyqt


    【解决方案1】:

    正如消息所示,代码包含sys.exit(app.exec_()),它将执行GUI,然后调用退出例程。你从一个交互式提示中调用了它,所以它没有退出,而是告诉你你试图从你调用的东西中退出。如果您希望能够从交互式提示中调用此代码而不会出现错误,只需删除退出部分,将sys.exit(app.exec_()) 更改为app.exec_()

    【讨论】:

    • 只是为了扩展解释:将sys 视为Python 本身。因此,当您的 GUI 完成执行时,正如@mdurant 所说,您是在告诉 python 退出自身……但您却处于交互式环境中。如果您从终端运行或在独立应用程序中运行,这仍然是很好的代码,但在交互式环境中您试图退出交互式环境的核心组件(python),这就是为什么它被认为是错误。
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