Python随机发牌员 - 面牌计数器不正确计数

Question

我正在练习为课堂编写这个程序。我必须发牌直到发完四个 A，最后，我还必须计算发了多少张牌（J、Q、K）。我没有为卡片名称制作字典，因为我的老师特别告诉我们要执行随机整数命令。但是，除了人脸计数器 (f_counter) 之外，一切都正常。由于某种原因，它总是少一张脸牌。有谁知道为什么？谢谢！

print("You were dealt:\n")

import random

# This is the initial counter for the number of cards dealt.
t_counter = 0

# This is the initial counter for the number of aces dealt.
a_counter = 0

# This is the initial counter for the number of face cards dealt.
f_counter = 0

# This is so both a rank and a suit are dealt.
r = random.randint(1,13)
s = random.randint(1,4)

while a_counter < 4:

    # This counts and tells the user of each card dealt that isn't an ace.
    r = random.randint(1,13)
    s = random.randint(1,4)
    t_counter += 1

    if r == 11:
        rank = "Jack"
    elif r == 12:
        rank = "Queen"
    elif r == 13:
        rank = "King"
    elif r > 1:
        rank = r

    if s == 1:
        suit = "Spades"
    elif s == 2:
        suit = "Hearts"
    elif s == 3:
        suit = "Diamonds"
    elif s == 4:
        suit = "Clubs"
    print("Card",t_counter,': A',rank,"of",suit,)

   # This counts the aces.
    if r == 1:
        a_counter += 1
        print("An Ace of",suit,"!")

    # This counts the face cards.
    if r == 11 or r == 12 or r == 13:
        f_counter += 1

    # This allows up to four aces and also prints the number of face cards as the last thing.
    if a_counter == 4:
        print("You got",f_counter,"face cards!")
        break

Answer 1

我想我找到了。考虑一下你有一张人脸卡的情况。

令 r = 11。

排名 -> '杰克'

西装 -> 任何东西

print('随便什么的杰克')

增加 f_counter

// 下一次迭代

令 r = 1

通过设置 rank 的 if 语句，因为 rank 不是 11,12,13 或 > 1，因此 rank = 'Jack'

print('其他西装的杰克')

增加a_counter（因为roll r = 1）

消除增加 f_counter 的可能性

因此，您打印了一张没有增加 f_counter 的面卡。

Answer 2

我对您的程序进行了一些更改。让我知道这是否能提供您想要的输出，我可以解释主要变化。

rank = ''

while a_counter < 4:

    # This counts and tells the user of each card dealt that isn't an ace.
    r = random.randint(1,13)
    s = random.randint(1,4)
    t_counter += 1


    if s == 1:
        suit = "Spades"
    elif s == 2:
        suit = "Hearts"
    elif s == 3:
        suit = "Diamonds"
    elif s == 4:
        suit = "Clubs"

    if r == 11:
        rank = "Jack"
        f_counter += 1
    elif r == 12:
        rank = "Queen"
        f_counter += 1
    elif r == 13:
        rank = "King"
        f_counter += 1
    elif r > 1 and r < 11:
        rank = r
    elif r == 1:
        rank == "Ace"
        a_counter += 1

    if r == 1:
        print("Card %d: An Ace of %s! **") % (t_counter, suit)
    else:
        print("Card %d: a %s of %s") % (t_counter, rank, suit)

    if a_counter == 4:
        print("You got %d face cards!") % (f_counter)
        break

这似乎对我有用，除了你的程序中没有任何东西可以防止同一张卡出现两次（或更多）......