通过参数从 JSON 中获取数据集

Question

尝试使用我的参数从 JSON 中查找唯一数据集。

我有 JSON“userDetails”：

{
"userDetails": [
                {
                "name": "Sabine",
                "imageUrl" :"https://randomuser.me/api/portraits/men/82.jpg",
                "content": [
                            {
                            "type": "video",
                            "url": "https://storage.googleapis.com/coverr-main/mp4/Travaho.mp4"
                            },
                            {
                            "type": "image",
                            "url": "https://picsum.photos/640/1136/?image=281"
                            }
                            ]
                },
                {"name": "Keila Maney",
                "imageUrl" :"https://randomuser.me/api/portraits/women/81.jpg",
                "content": [
                            {
                            "type": "image",
                            "url": "https://picsum.photos/640/1136/?image=273"
                            },
                            {
                            "type": "video",
                            "url": "http://commondatastorage.googleapis.com/gtv-videos-bucket/sample/ForBiggerBlazes.mp4"
                            }
                            ]
                }
                ]

}

我知道我的用户是 Keila Maney（我的代码中有用户属性）并且需要将该参数发送到 JSON，并且只接收返回 Keila Maney strong> 属性（就是imageUrl, content(type, url)）然后解析。

有没有标准的 JSON 搜索方法？

提前致谢！

Answer 1

Json 示例：

{  
  "places": [  
    {  
      "name": "Ulrikh",
      "id": 555,
    },  
    {  
      "name": "Place 2",  
      "id": 1,  
    }
]  
} 

呼叫：

 self.getDataByID(id: 555)

Swift 方法：

func getDataByID(id : Int) {
        let data = self.getData()
        
        
            for i in 0..<data.count
            {
            if(Int((((data as NSDictionary)["places"] as! NSArray)[i] as! NSDictionary)["id"] as! Int) == id)
            {
                print("here is result:")
                print((((data as NSDictionary)["places"] as! NSArray)[i]))
            }
        }
    }
    
    func getData() -> NSDictionary {
        do{
            let path = Bundle.main.path(forResource: "test", ofType: "json")
            let jsonData = NSData(contentsOfFile: path!)
            let jsonResult:NSDictionary!  = try JSONSerialization.jsonObject(with: jsonData! as Data , options: JSONSerialization.ReadingOptions.mutableContainers) as! NSDictionary
            return jsonResult
        } catch let error as NSError {
            print(error)
        }
        
        return NSDictionary()
    }

不用谢:)

Answer 2

只需创建 UserDetails 对象，例如：var userData: [UserDetails]? 并在循环中检查userData[x].name == "Keila Maney"。那么这个 x 将成为 Keila Maney 的索引，您可以获取它的所有数据。将您的 json 数据绑定到 UserModel 对象后。这些是您将从 json 创建的三个类

1. 用户模型

   struct UserModel : Codable {
   let userDetails : [UserDetails]?
   
   enum CodingKeys: String, CodingKey {
   
        case userDetails = "userDetails"
   }
   
   init(from decoder: Decoder) throws {
      let values = try decoder.container(keyedBy: CodingKeys.self)
      userDetails = try values.decodeIfPresent([UserDetails].self, forKey:.userDetails)
   }
   
   }
   

2. 用户详情

   struct UserDetails : Codable {
   let name : String?
   let imageUrl : String?
   let content : [Content]?
   
   enum CodingKeys: String, CodingKey {
   
       case name = "name"
       case imageUrl = "imageUrl"
       case content = "content"
   }
   
   init(from decoder: Decoder) throws {
       let values = try decoder.container(keyedBy: CodingKeys.self)
       name = try values.decodeIfPresent(String.self, forKey: .name)
       imageUrl = try values.decodeIfPresent(String.self, forKey: .imageUrl)
       content = try values.decodeIfPresent([Content].self, forKey: .content)
   }
   
   }
   

3. 内容

   struct Content : Codable {
   let type : String?
   let url : String?
   
   enum CodingKeys: String, CodingKey {
   
       case type = "type"
       case url = "url"
   }
   
   init(from decoder: Decoder) throws {
       let values = try decoder.container(keyedBy: CodingKeys.self)
       type = try values.decodeIfPresent(String.self, forKey: .type)
       url = try values.decodeIfPresent(String.self, forKey: .url)
   }
   
   }