在 IOS 应用程序上读取返回值 php

Question

您好，我正在编写一个 ios swift 3 应用程序来与网站通信，该应用程序在做了很多事情后应该返回一个 false 或 true 的类型值，但它不会发生你可以告诉我我在哪里错误以及如何纠正错误！

快速返回值： ....response = 可选（{ URL：“http://....myurl.php”}.....

SWIFT 代码：

let myUrl = URL(string: "http://....myurl.php");

var request = URLRequest(url:myUrl!)

request.httpMethod = "POST"// Compose a query string

let postString = "username=James&password=Bond";

request.httpBody = postString.data(using: String.Encoding.utf8);

let task = URLSession.shared.dataTask(with: request) { (data: Data?, response: URLResponse?, error: Error?) in

    if error != nil
    {
        print("error=\(error)");
       // return false
    }

    print("response = \(response)")

}
task.resume()

return 0;

PHP 代码：

include 'user.php';

$user = new User();
$username= $_REQUEST["username"];
$password = $_REQUEST["password"];

 if($user->login($username,$password)==true){
        echo json_encode("true"); 
 }

 else{
     echo json_encode("false"); 
 }

错误图片：

Answer 1

您需要查看数据而不是响应。 也许您应该将返回值封装在 PHP 代码中，例如：

if($user->login($username,$password)==true){
    echo '{"success":true}';
 }else{
     echo '{"success":false}';
 }

然后快速得到结果：

func login(request_completed:@escaping (_ succeded:Bool) -> ()) {
    let myUrl=URL(string: "http://....myurl.php");
    var request=URLRequest(url:myUrl!)
    request.httpMethod="POST"
    let postString = "username=James&password=Bond";
    request.httpBody = postString.data(using: String.Encoding.utf8);

    let task=URLSession.shared.dataTask(with: request, completionHandler: { data, response, error in
        guard data != nil else {
            print("no data found")
            request_completed(false)
            return
        }

        do{
            if let jsonData=try JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers) as? NSDictionary{
                print(jsonData)
                let success=jsonData.value(forKey: "success") as! Bool
                if success{
                    print("login succeded")
                    request_completed(true)
                    return
                 }else{
                    print("login failed")
                    request_completed(false)
                    return
                }
            }else{
                print("could not parse json")
                request_completed(false)
            }
        }catch{
            print("request failed")
            request_completed(false)
        }
    })
    task.resume()
}