如何使用新的 Apple Swift 语言发布 JSON

Question

我正在（尝试）学习 Swift 的 Apple 语言。我在 Playground 并使用 Xcode 6 Beta。我正在尝试对本地 NodeJS 服务器进行简单的 JSON 发布。我已经用谷歌搜索过了，主要教程解释了如何在项目中而不是在 PLAYGROUND 中进行操作，而不是写愚蠢的想法：“谷歌搜索”或“很明显”或“查看此链接”或从不-测试和非功能代码

这就是我正在尝试的：

var request = NSURLRequest(URL: NSURL(string: "http://localhost:3000"), cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)

var response : NSURLResponse?
var error : NSError?

NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &error)

我试过了：

var dataString = "some data"

var request = NSMutableURLRequest(URL: NSURL(string: "http://posttestserver.com/post.php"))
request.HTTPMethod = "POST"

let data = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)

var requestBodyData: NSData = data
request.HTTPBody = requestBodyData

var connection = NSURLConnection(request: request, delegate: nil, startImmediately: false)

println("sending request...")
connection.start()

谢谢！ :)

Answer 1

Nate 的回答很棒，但我必须更改 request.setvalue 才能在我的服务器上工作

// create the request & response
var request = NSMutableURLRequest(URL: NSURL(string: "http://requestb.in/1ema2pl1"), cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
var response: NSURLResponse?
var error: NSError?

// create some JSON data and configure the request
let jsonString = "json=[{\"str\":\"Hello\",\"num\":1},{\"str\":\"Goodbye\",\"num\":99}]"
request.HTTPBody = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: true)
request.HTTPMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")

// send the request
NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &error)

// look at the response
if let httpResponse = response as? NSHTTPURLResponse {
    println("HTTP response: \(httpResponse.statusCode)")
} else {
    println("No HTTP response")
}

Answer 2

看起来你有所有正确的部分，只是顺序不正确：

// create the request & response
var request = NSMutableURLRequest(URL: NSURL(string: "http://requestb.in/1ema2pl1"), cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
var response: NSURLResponse?
var error: NSError?

// create some JSON data and configure the request
let jsonString = "json=[{\"str\":\"Hello\",\"num\":1},{\"str\":\"Goodbye\",\"num\":99}]"
request.HTTPBody = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: true)
request.HTTPMethod = "POST"
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")

// send the request
NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &error)

// look at the response
if let httpResponse = response as? NSHTTPURLResponse {
    println("HTTP response: \(httpResponse.statusCode)")
} else {
    println("No HTTP response")
}

Answer 3

这是使用异步请求的一种不同的方法。您也可以通过这种方式使用同步方法，但由于上面的每个人都使用同步请求，我想改为显示异步请求。另一件事是这样看起来更干净、更容易。

    let JSONObject: [String : AnyObject] = [
        "name" : name,
        "address" : address,
        "phone": phoneNumber
    ]

    if NSJSONSerialization.isValidJSONObject(JSONObject) {
        var request: NSMutableURLRequest = NSMutableURLRequest()
        let url = "http://tendinsights.com/user"

        var err: NSError?

        request.URL = NSURL(string: url)
        request.HTTPMethod = "POST"
        request.cachePolicy = NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData
        request.setValue("application/json", forHTTPHeaderField: "Content-Type")
        request.HTTPBody = NSJSONSerialization.dataWithJSONObject(JSONObject, options:  NSJSONWritingOptions(rawValue:0), error: &err)

        NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue()) {(response, data, error) -> Void in
            if error != nil {

                println("error")

            } else {

                println(response) 

            }
        }
    }