Сannot 将“Obj”类型的值转换为预期的参数类型“Obj”

Question

我有一个来自服务器的数组。

我的问题是当我想将对象添加到 大批。如何解决此问题并使用对象数组 来自服务器？？

返回数据示例

[
    {
        "empId": 1970083,
        "empCode": "2007",
        "empName": "Emp Test",
        "monthClosed": 0,
        "monthApproved": 0,
        "approvedDate": 0,
        "employerName": "Name",
        "employerApproval": 1, 
        "employerApprovalDate": "2020-09-02 17:22:51.843"
    },
]

这个结构来接收这个数据

struct GetMonthSummaryObj: Codable {
    
    var empId: Int?
    var empCode: String?
    var empName: String?
    var monthClosed: Int?
    var monthApproved: Int?
    var approvedDate: Int?
    var employerName: String?
    var employerApproval: Int?
    var employerApprovalDate: String?
}

这是 ViewModel 中的一种方法，用于添加来自数组的数据并将其用于表。例如，显示或表格中的单元格数

func setEmployees(employees: [GetMonthSummaryObj?]) {
        employeesList = []
        
        employees.forEach {_ in
            employeesList.append(CloseMonthEmpListItem(employee: employees))


 //Error - Cannot convert value of type '[GetMonthSummaryObj?]' to expected argument type 'GetMonthSummaryObj'
        }
        
    }

在这里我创建了一个数组对象来使用它

class CloseMonthEmpListItem: Equatable, NSCopying {

    var employee: GetMonthSummaryObj

       init(employee: GetMonthSummaryObj) {
           self.employee = employee
         
       }
    static func == (lhs: CloseMonthEmpListItem, rhs: CloseMonthEmpListItem) -> Bool {
        return lhs.employee.empId == rhs.employee.empId
     }
     
     func copy(with zone: NSZone? = nil) -> Any {
         let copy = CloseMonthEmpListItem(employee: employee)
         return copy
     }
}

Answer 1

这个 init(employee: GetMonthSummaryObj) 接受GetMonthSummaryObj 类型，而你传递[GetMonthSummaryObj?] 这不起作用

你需要更换

employees.forEach {_ in
   employeesList.append(CloseMonthEmpListItem(employee: employees)) 
}

有

let res = employees.compactMap{ $0 }
res.forEach { item in
    employeesList.append(CloseMonthEmpListItem(employee:item)) 
}

或

let res = employees.compactMap{ $0 }
employeesList = res.map { CloseMonthEmpListItem(employee:$0) }