如何在 Python 中加密数据？

Question

如何使用 Python 加密数据？
就像数据是Hello, I am a coder!
如果密码是123AAVVC
那么如何将Hello, I am a coder加密成0000 0000 0101 0101等不可读的字符
并且只有在密码为"123AAVVC"时才能解密为Hello, I am a coder。

这是我的代码：

def InputPassword():
    Msg = "Enter your password: "
    InputPassword = input(Msg)
    return InputPassword

def InputData():
    Msg = "Enter your data: "
    InputData = input(Msg)
    return InputData


def Encode():
    Psd = InputPassword()
    Data = InputData()
    LenPsd = len(Psd)
    if LenPsd >= 8: #This will allow user to enter password that has 8 or more character
        if Psd:
            pass
            #Rest of the code, I know till here.
        else:
            print("Error!")
    else:
        print("Passord is too short!")

if __name__ == '__main__':
    try:
        Encode()
    except:
        pass

请帮我编写这个 prgram，我是 Python 编程新手
提前致谢。

Answer 1

听起来您想要加密，因为您使用的是密码。

你可以使用像 pycryptodome 这样简单的东西来制作牢不可破的密码：

def __EncryptionBase(text, password):
    iv = get_random_bytes(16)
    cipher = AES.new(password, AES.MODE_CBC, iv=IV)
    padded_data = pad(text.encode(), cipher.block_size)
    ciphertext = cipher.encrypt(padded_data)
    return IV + ciphertext

def __DecryptionBase(text, password, IV):
    cipher = AES.new(password, AES.MODE_CBC, iv=IV)
    paddedBytes = cipher.decrypt(text)
    originalBytes = unpad(paddedBytes, cipher.block_size)
    return originalBytes

如果您需要进一步简化上述代码，请发表评论

---

根据要求提供没有任何包和几行代码的密码。 几乎是最简单的加密，给你;D

state = [None] * 256
p = q = None


def setKey(key):
    global p, q, state
    key = [ord(c) for c in key]
    state = [n for n in range(256)]
    p = q = j = 0
    for i in range(256):
        if len(key) > 0:
            j = (j + state[i] + key[i % len(key)]) % 256
        else:
            j = (j + state[i]) % 256
        state[i], state[j] = state[j], state[i]


def byteGenerator():
    global p, q, state
    p = (p + 1) % 256
    q = (q + state[p]) % 256
    state[p], state[q] = state[q], state[p]
    return state[(state[p] + state[q]) % 256]


def encrypt(inputString, password):
    setKey(password)

    a = [ord(p) ^ byteGenerator() for p in inputString]
    b = ""
    for i in a:
        b += str(i) + ","
    b = b[:-1]
    return b


def decrypt(YourCipheredNumericList, password):
    setKey(password)
    a = YourCipheredNumericList.split(",")
    if a[-1] == "":
        a.pop()
    b = []
    for i in a:
        b.append(int(i))
    return "".join([chr(c ^ byteGenerator()) for c in b])

a = encrypt("hello world", "123")
print(a)
b = decrypt(a, "123")
print(b)

这是对你的挑战...... 使用上面的简单加密，我向您创建了两条隐藏消息，尝试破解它们并告诉我我的秘密：D

容易折断（不到 2 分钟）：

MyFirstSecretMessage = decrypt("66,28,211,12,44,178,181,41,254,43,244,148,110,52,56,175", *MySecretPassword*)

非常难（我个人无法破坏此消息）

MySecondSecretMessage = decrypt("129,189,215,167,37,158,208,75,4,161,96,213", *MySecretPassword*)