具有多个字段的 PHP 搜索

Question

我想使用带有多个字段搜索选项（例如姓名、学院、部门、年份、国籍等）的 ajax 方法搜索数据。我有用于搜索的插入名称，其余字段为空，而不是进入 foreach 循环，但是这个 if (isset($_GET[$field]) && !empty($_GET['$field'])) 条件不成功并且去了否则循环

  $fields = array(
  'name' => TRUE,
  'gender' => TRUE,
  'colf' => TRUE,
  'deptf' => TRUE,
  'natf' => TRUE,
  'fstatusf' => TRUE,
  'fyearf' => TRUE
  );
 foreach ($fields as $field => $like) {
  if (isset($_GET[$field]) && !empty($_GET['$field'])) {
    $value = $_GET[$field];
    $search[] = $field . ( $like ? ('LIKE "%' . $value . '%"') : ('="' . $value . '"') );
       }
 } 
  if ($search) {
  $sql = 'SELECT * FROM fmaf WHERE ' . implode(' or ' . $search);
  }

else{
$sql="SELECT * FROM fmaf";

    }

Answer 1

最后我找到了解决方案，感谢 cFreed 和其他帮助我的人。我主要担心的是，如果用户只想搜索一个字段或多个字段，那么下面的答案对我有帮助，也可能对某人有用：

if (empty($_GET['name']) && empty($_GET['gender']) && empty($_GET['colf']) && empty($_GET['deptf']) && empty($_GET['natf']) && empty($_GET['fstatusf']) && empty($_GET['fyearf']))
{
    $sql="select * from fmaf ";
}
else
{
 $wheres = array();

$sql = "select * from fmaf where ";

if (isset($_GET['name']) and !empty($_GET['name']))
{
    $wheres[] = "name like '%{$_GET['name']}%' ";
} 

if (isset($_GET['gender']) and !empty($_GET['gender']))
{
    $wheres[] = "gender = '{$_GET['gender']}'";
} 

if (isset($_GET['colf']) and !empty($_GET['colf']))
{
    $wheres[] = "college = '{$_GET['colf']}' ";
} 

if (isset($_GET['deptf']) and !empty($_GET['deptf']))
{
    $wheres[] = "department = '{$_GET['deptf']}' ";
} 

if (isset($_GET['natf']) and !empty($_GET['natf']))
{
    $wheres[] = "nationality = '{$_GET['natf']}' ";
} 

if (isset($_GET['fstatusf']) and !empty($_GET['fstatusf']))
{
    $wheres[] = "finalstatus = '{$_GET['fstatusf']}' ";
}

if (isset($_GET['fyearf']) and !empty($_GET['fyearf']))
{
    $wheres[] = "fyear = '{$_GET['fyearf']}' ";
} 

foreach ( $wheres as $where ) 
{
$sql .= $where . ' AND ';   //  you may want to make this an OR
  }
 $sql=rtrim($sql, "AND "); 

     }

Answer 2

您需要根据请求构建查询。 一个玩具示例是这样的：

$sql = "select * from student where 1 = 1".(isset($name)?" AND name like '%$name%":"").(isset($country)?" AND country = '$country'":"").";";

Answer 3

你可以用一个简单的方法，可以面对任何情况，像这样：

// define searchable fields, with option for LIKE|EQUAL (TRUE|FALSE)
$fields = [
  'name' => TRUE,
  'country' => TRUE,
  'address' => TRUE,
  'gender' => FALSE,
  'state' => FALSE
];
foreach ($fields as $field => $like) {
  if (isset($_GET[$field]) AND !empty($_GET['$field'])) {
    $value = $_GET[$field];
    // prepare WHERE condition item, depending on LIKE option
    $search[] = $field . (
      $like ? ('LIKE "%' . $value . '%"') : ('="' . $value . '"')
    );
  }
}
if ($search) {
  $sql = 'SELECT * FROM student WHERE ' . implode(' AND ' . $search);
}