如何在 for 循环中排序（swift）[重复]

Question

let vehicles = ["unicycle" : 1, "bicycle":2, "tricycle":3, "quad bike": 4]
for (vehicleName, wheelCount) in vehicles {

    print (" \(vehicleName) has \(wheelCount) wheels")
      
}`

打印输出结果为：

四轮车有 4 个轮子 独轮车有 1 个轮子 三轮车有 3 个轮子 自行车有两个轮子

我怎样才能根据轮子的数量对它们进行排序，所以打印输出可以是这样的：

独轮车有 1 个轮子 自行车有 2 个轮子 三轮车有3个轮子 四轮摩托车有 4 个轮子

Answer 1

你可以使用sorted：

let vehicles = ["unicycle" : 1, "bicycle": 2, "tricycle": 3, "quad bike": 4]
let sortedVehicles = vehicles.sorted { $0.value < $1.value }
for (vehicleName, wheelCount) in sortedVehicles {
    print ("\(vehicleName) has \(wheelCount) wheels")
}

输出：

unicycle has 1 wheels
bicycle has 2 wheels
tricycle has 3 wheels
quad bike has 4 wheels

Answer 2

let vehicles = ["unicycle" : 1, "bicycle":2, "quad bike": 4, "tricycle":3]
let sortedVehicles = vehicles.sorted { $0.1 < $1.1 }
print(sortedVehicles) //Prints [(key: "unicycle", value: 1), (key: "bicycle", value: 2), (key: "tricycle", value: 3), (key: "quad bike", value: 4)]
sortedVehicles.forEach {
    print("\($0.key) has \($0.value) wheels")
}

结果：

unicycle has 1 wheels
bicycle has 2 wheels
tricycle has 3 wheels
quad bike has 4 wheels

Answer 3

let vehicles = ["unicycle" : 1, "bicycle" : 2, "tricycle" : 3, "quadbike" : 4].sorted {
    return $0.value > $1.value
}
for (vehicieName, wheelCount) in vehicles {
    print("\(vehicieName) has \(wheelCount) wheels")
}