如何对 Excel 工作表中的列进行排序

Question

所以我了解了排序在 Python 中的工作原理。如果我把...

a = (["alpha2A", "hotel2A", "bravo2C", "alpha2B", "tango3B", "alpha3A", "zulu.A1", "foxtrot8F", "zulu.B1"]
a.sort()
print a

我会得到...

'alpha2A', 'alpha2B', 'alpha3A', 'bravo2C', 'foxtrot8F', 'hotel2A',  'tango3B', 'zulu.A1', 'zulu.B1']

但是，我想对 Excel 工作表中的列进行排序，所以我尝试了...

isv = open("case_name.csv", "w+")
a = (["case_name.csv"[2]])
a.sort()
print a

得到了回报……

['s']

我知道它正在返回文件名中的第三个字母，但我如何对其进行排序并返回 Excel 工作表的整个列？

更新：新代码

import csv
import operator

with open('case_name.csv') as infile:
    data = list(csv.reader(infile, dialect=csv.excel_tab))

data.sort(key=operator.itemgetter(2))

with open('case_name_sorted.csv', 'w') as outfile:
    writer = csv.writer(outfile, dialect='excel')
    writer.writerows(data)

print(sum(1 for row in data if len(row) < 3))

然后它返回

data = list(csv.reader(infile, dialect=csv.excel_tab))
_csv.Error: new-line character seen in unquoted field - do you need to open the file in universal-newline mode?

Answer 1

import csv
import oprator

# read the data from the source file
with open('case_name.csv') as infile:
    data = list(csv.reader(infile, dialect='excel'))

# sort a list of sublists by the item in index 2
data.sort(key=operator.itemgetter(2))


# time to write the results into a file
with open('case_name_sorted.csv', 'w') as outfile:
    writer = csv.writer(outfile, dialect='excel')
    writer.writerows(data)