拉取仅与多行中的一组值匹配的特定记录

Question

我正在尝试查找只有一组确切收件人的所有对话。我的表格如下所示：

Conversation
---------------
id | some other fields

User
---------------
id | some other fields

Recipients
--------------
id | conversation_id | user_id | some other fields
1  | 1               | 1
2  | 1               | 2        
3  | 2               | 1
4  | 2               | 2                
5  | 2               | 3
6  | 3               | 1
7  | 3               | 3

使用上面的方法我想得到conversation_id 1，我唯一知道的是user_id的[1,2]，但我不想要任何其他记录我将如何去做。

Answer 1

您可以在conversation_id 上进行分组，然后使用having 过滤掉正确的对话。在下面的查询中，第一行要求 user_id 1 和 2 都存在。第二行要求它不包含任何其他user_id：

select  conversation_id
from    recipients
group by
        conversation_id
having  count(distinct case when user_id in (1,2) then user_id end) = 2
        and count(case when user_id not in (1,2) then 1 end) = 0

Answer 2

如果我理解正确：

 SELECT id
 , conversation_id 
 , user_id
 , ... other columsn
 FROM Recipients 
 WHERE converstaion_id = 1
 AND user_id IN (1,2)

Answer 3

select c.* from Conversation c 
  where (select count(distinct user_id) from Recipients 
     where conversation_id=c.id and user_id in (<USER-IDS>))=<NUMBER-OF-USERS>

其中 是逗号分隔的用户 ID， 是这些用户的确切数量，例如2 在你的例子中。

Answer 4

首先找到具有不在您列表中的 user_id 的会话 ID（内部子查询）然后查找不在此列表中的会话 ID

SELECT DISTINCT conversation_id
FROM         dbo.Recipients
WHERE     (conversation_id NOT IN
                          (SELECT     Recipients_1.conversation_id
                            FROM          dbo.Recipients AS Recipients_1 LEFT OUTER JOIN
                                                       (SELECT id AS user_id
                                                         FROM          User
                                                         WHERE      (id IN (1, 2))) AS tbl_user ON tbl_user.user_id = Recipients_1.user_id
                            WHERE      (tbl_user.user_id IS NULL)))