在没有全局（python）的另一个函数中使用try函数中的变量

Question

如何在 main 函数的guessfunction() 中使用变量“guess”（对于范围（1,6）中的i？我收到未定义guess 的错误。最初，没有guessfunction，一切正常，但我想增加用户输入错误的可能性，这让我陷入了困境。 我在 stackexchange 上看到在函数中使用 global 是不好的做法，但即使使用 global 我也不知道如何解决我的问题。 如果可以从函数中获取变量，是否还有一种方法可以更改 int(guess)？ 谢谢！

import random, sys

print("Hello. What is your name?")
name = str(input())
print("Well, " + name + ", I am thinking of a number between 1 and 20.")
number = random.randint(1, 20)

def guessfunction():
    print("Take a guess.")
    guess = input()
    for number_attempts in range(0,3):
        try:
            return guess
        except ValueError:
            print("Please enter a number in figures not as a word")
    print("You didn't enter a number in figures after 3 tries, program ended")
    sys.exit()
    
for i in range(1,6):
    guessfunction()
    if int(guess) != number:
        if int(guess) < number:
            print("Your guess is too low")
        else:
            print("Your guess is too high")
    elif int(guess) == number:
        print("Good job, " + name + "! You guessed my number in " + str(i) + " guesses")
        sys.exit()
print("Nope. The number I was thinking of was " +str(number))

Answer 1

你需要在你的 for 循环中初始化它：

guess = guessfunction()